Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 10)
10.
A single-phase sinusoidal voltage of 120 V is connected to a 90 
load. Current in the circuit is
load. Current in the circuit isDiscussion:
11 comments Page 1 of 2.
Dilawar khan said:
6 years ago
Simple Ohm's law I =v/r.
I=V/R=120/90=4/3=1.33A.
I=V/R=120/90=4/3=1.33A.
(1)
Rachana said:
1 decade ago
120v/90 = 4/3 = 1.33 a
S.Anantha vivek narayanan said:
1 decade ago
I=V/R=120/90=1.333A
LAVANYA said:
1 decade ago
By using ohms law.... I=V/R.
VIVEK KUMAR said:
1 decade ago
I=V/R=120/90=1.33A
M.gurudas said:
1 decade ago
Current=voltage/resistance
Here voltage=120vac,
Resistance= 90ohms,
Current=?,
There fore
Current = 120/90
Current = 1.33amp.
Here voltage=120vac,
Resistance= 90ohms,
Current=?,
There fore
Current = 120/90
Current = 1.33amp.
Palaniappan said:
1 decade ago
Ohms law is only applicable to dc circuit. But it is AC?
Ammad Khan said:
1 decade ago
Phase 1:
120<0/90=1.33.
Phase 2:
120<120/90 = -0.0055.
1.33-.0055 = 1.33A.
120<0/90=1.33.
Phase 2:
120<120/90 = -0.0055.
1.33-.0055 = 1.33A.
M.keerthi said:
10 years ago
Simple ohms law i = v/r.
= 120/90 = 1.33 a.
= 120/90 = 1.33 a.
GANESWAR SAHOO said:
10 years ago
Simple Ohm's law I = v/r.
I = V/R = 120/90 = 4/3 = 1.33 A.
I = V/R = 120/90 = 4/3 = 1.33 A.
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