Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 8)
8.
The parallel combination of a 470 
resistor and a 1.5 k resistor is in series with the parallel combination of five 1 k resistors. The source voltage is 50 V. The percentage of the load current through any single 1 k resistor is
resistor and a 1.5 k resistor is in series with the parallel combination of five 1 k resistors. The source voltage is 50 V. The percentage of the load current through any single 1 k resistor isDiscussion:
22 comments Page 2 of 3.
SIVA said:
1 decade ago
@Meena.
You are wrong in parallel current through all branches is not same :).
You are getting the right answer because all resistors are same value so the currents drawn by them is also same :).
You are wrong in parallel current through all branches is not same :).
You are getting the right answer because all resistors are same value so the currents drawn by them is also same :).
DEEPU said:
1 decade ago
@Meena.
Exactly your right for same set of resistors. And even we can calculate the same in for different resistors values.
Exactly your right for same set of resistors. And even we can calculate the same in for different resistors values.
Parneet kaur said:
1 decade ago
Of course @Meena you are right.
But this simple and quick method is only applied when all the resistors are of same value. Otherwise you can't applied when resistors are of different values are given.
What is the simple method when resistors are of different values are given?
But this simple and quick method is only applied when all the resistors are of same value. Otherwise you can't applied when resistors are of different values are given.
What is the simple method when resistors are of different values are given?
Shashank said:
9 years ago
Actually, they ask for a percentage. So, for 51K ohms resistor 50V/200ohm = 0.25A.
Again 50/1 Kohm = 0.05A, therefore 0.05/0.25*100 = 20%.
Again 50/1 Kohm = 0.05A, therefore 0.05/0.25*100 = 20%.
(1)
Satish Reddy N said:
9 years ago
@Priya,
Where does that 1/4 comes from I am not getting that?
Where does that 1/4 comes from I am not getting that?
Puja said:
9 years ago
You are right @Shashank.
But can you tell me what is the formula if there is not same resistance in parallel?
But can you tell me what is the formula if there is not same resistance in parallel?
Megha said:
9 years ago
Thank you for the explanation.
Don said:
9 years ago
Thanks for the explanation of the answer.
Vandana said:
8 years ago
Thank you @Meenakshi.
Richa said:
8 years ago
Please somebody give me current divider formula with explanation.
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