Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 9)
9.
A certain Wheatstone bridge has the following resistor values: R1 = 10 k
, R2 = 720 , and R4 = 2.4 k. The unknown resistance is
, R2 = 720 , and R4 = 2.4 k. The unknown resistance is24
2.4
300
3,000
Discussion:
28 comments Page 3 of 3.
Mahe said:
1 decade ago
In wheatstone bridge product of two opposite resistors is equal to the another product. Here R1 R2 and R3 wherever we can mention. So these kind of problems we need a circuit or figure.
Ankit Tiwari said:
1 decade ago
Normal formula apply here R1/R2 = R3/R4.
Meenakshi said:
1 decade ago
Here Rv means variable resistance i.e., generally R3.
Formula R4 = R2R3/R1, but here R4 is given, we have to fnd R1, so eqn becomes R1 = R2R3/R4.
Therefore R1 = 720*10k/2.4K = 3000 ohms.
Formula R4 = R2R3/R1, but here R4 is given, we have to fnd R1, so eqn becomes R1 = R2R3/R4.
Therefore R1 = 720*10k/2.4K = 3000 ohms.
Keerthi said:
1 decade ago
Here Rv means R1 or R3?
Tamilarasan said:
1 decade ago
In a wheatstone bridge the ratio is equal (i.e. R1*R2=R3*R4).
So R2=R3*R4/R1. Sub the value. We will get the answer.
So R2=R3*R4/R1. Sub the value. We will get the answer.
Sai said:
1 decade ago
I agree with you anand.
Anand said:
1 decade ago
(R1/R2)=(R3/R4),So R4=(R2/R1)*R3
Ramu said:
1 decade ago
This will ans is correct but procedure is wrong.
Wheat stone bridge Rx= (R2/R1) *R3.
Wheat stone bridge Rx= (R2/R1) *R3.
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