Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 9)
9.
A certain Wheatstone bridge has the following resistor values: R1 = 10 k, R2 = 720 , and R4 = 2.4 k. The unknown resistance is
24
2.4
300
3,000
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
28 comments Page 2 of 3.

Engr Baloch said:   5 years ago
Agree @Jojo D.

The answer should be 33.33k Ohms, because the formula is R1/R2=R3/R4.

Ravi said:   1 decade ago
Formula: R1*R2 = R3*R4.

Therefore R3 = (R1*R2)/R4.

= (10k*720)/2.4 k.

= 3000 ohms.

Nouman said:   1 decade ago
@Meenakshi : How do we find R1 ? when its already been given in the question.

Parneet kaur said:   1 decade ago
@Ankit Tiwari.

Your formula is wrong. The correct formula is r1*r2=r3*r4.

Hardiksinh said:   6 years ago
Yes, R3 = 33.33, because the formula is R1R4=R2R3. Then R3= R1R4/R2.
(1)

Darshil said:   6 years ago
The correct formula is R1/R2 = R3/R4.
So the answer comes 33.3kOhm.

Abinash said:   3 years ago
R1/R2=R3/R4.
Or
R3=(R1/R2). R4
Ans =33.33k ohm.
(2)

MARI RAJ said:   7 years ago
Unknown resister R3=(R1/R2)*R4.
So, R3 = 33.3kohm.

W.b said:   6 years ago
R1/R2 = R3/R4.

THIS IS CORRECT FORMULA.

Piya said:   1 decade ago
But in wheatstone bridge: R2/R1 = R4/R3.


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