Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 10)
10.
On which of the following voltage range settings will a voltmeter present the minimum load on a circuit?
Discussion:
19 comments Page 1 of 2.
Heroth said:
6 years ago
The higher the rating of V meter, the higher its internal resistance. Since V meter is connected in parallel in circuit, to have minimum loading effect the V meter should have high internal resistance so that minimum amount of circuit current can pass through it. Thus, among the four options, the highest rating V meter is 1000V and thus it will result in minimum withdrawal of circuit current.
(4)
Jay tiwari said:
1 decade ago
@Yamini.
No its not possible to measure the load with voltage which is present by a voltmeter. But its true.
Voltage is inversely proportional to load on the system i.e. as load increases voltage decreases. But we can't measure individual voltmeter we need flowing current or opposing resistance.
No its not possible to measure the load with voltage which is present by a voltmeter. But its true.
Voltage is inversely proportional to load on the system i.e. as load increases voltage decreases. But we can't measure individual voltmeter we need flowing current or opposing resistance.
(1)
Geeta said:
3 years ago
Please, anyone explain it clearly to understand.
(1)
Ganesh said:
8 years ago
@Puja.
The voltage is inversely proportional to load. So the minimum load has maximum voltage so the answer is max voltage that is 1000V.
The voltage is inversely proportional to load. So the minimum load has maximum voltage so the answer is max voltage that is 1000V.
(1)
Jay tiwari said:
1 decade ago
@Yamini.
Voltmeter present means voltmeter shown minimum load on the circuit its means current flow in circuit is low then voltmeter shown volt in maximum value. So we say voltage range 1000v.
Voltmeter present means voltmeter shown minimum load on the circuit its means current flow in circuit is low then voltmeter shown volt in maximum value. So we say voltage range 1000v.
(1)
Dayal said:
1 decade ago
Here is the concept of relationship between load res & Voltage.
Since load is lesser as per question so the voltage value will be the higher one (having less voltage drop on account of less load in the ckt).
Since load is lesser as per question so the voltage value will be the higher one (having less voltage drop on account of less load in the ckt).
Gbenga said:
1 decade ago
For voltmeter, the maximum load current and maximum load Resistor is fixed.
i.e. the maximum voltage is fixed. Read or measured voltage in excess of this are dropped across an added series resistor.
So, Vtest = Vmeter + Vseries.
= Vmeter + Imeter * Rseries.
Since Vmeter and Imeter are fixed.
=> Vtest proportional to Rseries.
So, increasing Vtest will reqire increasing Rseries.
Also Rtotal = Rmeter + Rseries.
i.e. the maximum voltage is fixed. Read or measured voltage in excess of this are dropped across an added series resistor.
So, Vtest = Vmeter + Vseries.
= Vmeter + Imeter * Rseries.
Since Vmeter and Imeter are fixed.
=> Vtest proportional to Rseries.
So, increasing Vtest will reqire increasing Rseries.
Also Rtotal = Rmeter + Rseries.
Yamini upadhyay said:
1 decade ago
Explain please, this explanation is not clearing my doubt voltmeter present minimum load on the circuit.
Keerthi said:
1 decade ago
V = IR means V directly proportional to I. , then how can we say that, if voltage increases means current will decrease?
Ramu said:
1 decade ago
Explanation please.
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