Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 5)
5.
A voltage divider consists of two 68 k resistors and a 24 V source. The unknown output voltage is
12 V
24 V
0 V
6 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
40 comments Page 4 of 4.

Abrha said:   9 years ago
Thanks for your clear explanation @Sushma.

Rithu said:   9 years ago
Please explain me to understand it.

Vidhya Sri said:   8 years ago
Clear explanation, Thanks @Sushma.

Abhishek said:   8 years ago
Resistance in kilo ohm and answer in volt.

Ameesh devwrat said:   8 years ago
In a voltage divider circuit there are always 2 resistors in series say r1 nd r2.

The output is taken across say r2.

Then the output voltage will be;

Vo=(r2/r2+r1)vi.
Vi is input voltage.
Therefore;
Vo=(68/68+68)24=24/2=12.
(1)

Viswa said:   8 years ago
Great answer @Sushma.

Amresh said:   8 years ago
Unkown output voltage means voltage drop across the last element. Here bothresistance value is same so 12v is coming.

Nani said:   6 years ago
@All.

Hi, Here it is mentioned as a voltage divider. That means, its a simple series circuit across one voltage source.

Unless otherwise mentioning the output terminals, we cannot assume that the unknown voltage is across one of the resistance or so.

I think input data in the question has to be elaborated. Correct me, if I am wrong.

Sadik said:   6 years ago
Thanks @Sushma.
(2)

SHITAL said:   2 years ago
I think here applying voltage division rules this used only for resistors connected with voltage source if not then the converted number of resisters is only 2 resistor formate so,

If you find.

R0 =Vi* (R1/R1+R2).
R0=24* (68/68+68) =12.


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