Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 5)
5.
A voltage divider consists of two 68 k
resistors and a 24 V source. The unknown output voltage is

Discussion:
40 comments Page 3 of 4.
SHITAL said:
2 years ago
I think here applying voltage division rules this used only for resistors connected with voltage source if not then the converted number of resisters is only 2 resistor formate so,
If you find.
R0 =Vi* (R1/R1+R2).
R0=24* (68/68+68) =12.
If you find.
R0 =Vi* (R1/R1+R2).
R0=24* (68/68+68) =12.
Sagata said:
1 decade ago
We know voltage in one of the 68 ohm resistor is V=I.R1(R1=resistance of one of the resistors )
again V=(V/R).R1(R=total resistance of circuit.)
Hence,V=[24/(68+68)]*68=12V
Voltage divider rule is applicable for series circuit only because in series only voltage varies but not in paralel circuits.
again V=(V/R).R1(R=total resistance of circuit.)
Hence,V=[24/(68+68)]*68=12V
Voltage divider rule is applicable for series circuit only because in series only voltage varies but not in paralel circuits.
Nafish said:
1 decade ago
24V is divided into two part each= 24/2 = 12V
Bhavani said:
1 decade ago
I want explanation for this.
Thanks. !
Thanks. !
Isocuraphil said:
1 decade ago
Ok how come it is 12?
Ganeshbabu said:
1 decade ago
Thanks sushma.
Anand said:
1 decade ago
Nice Explanation Sushma...
Santhosh said:
1 decade ago
Thank you sushma.
Bala said:
1 decade ago
Thanks sushma.
Pradeep said:
1 decade ago
Thanks Sushma.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers