Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 5)
5.
A voltage divider consists of two 68 k
resistors and a 24 V source. The unknown output voltage is
resistors and a 24 V source. The unknown output voltage isDiscussion:
40 comments Page 2 of 4.
K vamsi said:
1 decade ago
Hello @Subhojit,
In this question these 2 resistors are in series and same value so voltage across any of the resistor is same I think if it is wrong tell me with clarity.
In this question these 2 resistors are in series and same value so voltage across any of the resistor is same I think if it is wrong tell me with clarity.
Mr. Kathiravan From Vellore said:
1 decade ago
Voltage Divider (Vout)=(R2/(R1+R2))xVin
= (68/(68+68))x24
= 12V
= (68/(68+68))x24
= 12V
Amresh said:
8 years ago
Unkown output voltage means voltage drop across the last element. Here bothresistance value is same so 12v is coming.
Dasu Namburi said:
1 decade ago
He is not specifying individual divider o/p voltage. He ask only o/p voltage means 24v(consumed at series resistors).
Narender said:
1 decade ago
1st draw the circuit diagram of the question then you will get the answer simply by observing the circuit diagram.
Shobitha K N said:
10 years ago
Voltage divider general formula:
Vout = (Z2/(Z1+Z2))*Vin.
Vout = (68/136)*24.
Vout = (1/2)*24.
Vout = 12.
Vout = (Z2/(Z1+Z2))*Vin.
Vout = (68/136)*24.
Vout = (1/2)*24.
Vout = 12.
(1)
Karthik holla said:
9 years ago
In voltage divider circuit if the resistance are same then output will be half of input voltage.
Dasu Namburi said:
1 decade ago
It is totally wrong because output voltage means consumed voltage except source so answer is 24.
CIRCUIT BREAKER said:
1 decade ago
Unknown out put voltage = (24*68)/(68+68).
= 12v.
= 12v.
Sri said:
1 decade ago
V2=V1R1(R1+R2) and putting the values we get 12
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