Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 14)
14.
A certain circuit is composed of two parallel resistors. The total resistance is 1,403 
. One of the resistors is 2 k. The other resistor value is
. One of the resistors is 2 k. The other resistor value is1,403
4.7 k
2 k
3,403
Discussion:
8 comments Page 1 of 1.
Hemant Vitthalrao Chunarkar said:
2 years ago
Rt = R1 + R2/R1*R2.
1403 = R1*2000/R1+2000.
1403(R1 + 2000) = 2000 * R1.
1403R1 + 2806000 = 2000 * R1.
1403R1 - 2000R1 = -2806000.
-597R1 = -2806000,
R1 = 4700.16 ohm.
R1 = 4.7 kohm.
1403 = R1*2000/R1+2000.
1403(R1 + 2000) = 2000 * R1.
1403R1 + 2806000 = 2000 * R1.
1403R1 - 2000R1 = -2806000.
-597R1 = -2806000,
R1 = 4700.16 ohm.
R1 = 4.7 kohm.
Shreedhar B said:
6 years ago
1403 = (2000*r2)/(2000+r2).
(2000+r2)(1403) = 2000r2.
2806+1403r2 = 2000r2.
2000r2-1403r2 = 2806.
597r2 = 2806.
r2 = 2806÷597.
r2 = 4.7k ohm.
(2000+r2)(1403) = 2000r2.
2806+1403r2 = 2000r2.
2000r2-1403r2 = 2806.
597r2 = 2806.
r2 = 2806÷597.
r2 = 4.7k ohm.
(1)
MARIRAJ said:
7 years ago
(1/Req)=(1/R1)+(1/R2).
Req=1403.
1/Req=7.12 * 10^-4.
(1/Rx)=(1\Req)-(1/2000) = 2.2* 10^-4.
And unknown resistance Rx= 4.7kΩ
Req=1403.
1/Req=7.12 * 10^-4.
(1/Rx)=(1\Req)-(1/2000) = 2.2* 10^-4.
And unknown resistance Rx= 4.7kΩ
Pritesh said:
7 years ago
Thanks for the answer @Bunty.
Mani said:
9 years ago
It is an easy method, thanks for explaining it @Bunty.
Bunty said:
1 decade ago
Assume 2nd resistor value is 'x'.
2000x/2000+x=1403.
2000x=1403 (2000+x).
2000x=2806000+1403x.
2000x-1403x=2806000.
597x=2806000.
X=2806000/597.
X=4700.16 ohm.
X=47kohm.
2000x/2000+x=1403.
2000x=1403 (2000+x).
2000x=2806000+1403x.
2000x-1403x=2806000.
597x=2806000.
X=2806000/597.
X=4700.16 ohm.
X=47kohm.
Surajit said:
1 decade ago
Let,the unknown resistance is x.
x is parallel to 2k or 2000 ohm and total resistance is 1403
(x*2000)/(x+2000)=1403
or,x=((2000*1403)/(2000-1403))
=4.7 k ohm
x is parallel to 2k or 2000 ohm and total resistance is 1403
(x*2000)/(x+2000)=1403
or,x=((2000*1403)/(2000-1403))
=4.7 k ohm
Trupti said:
1 decade ago
By rule of parallel circuit
(1/r)+(1/2000)=1/1403
By solving we get r=4.7k
(1/r)+(1/2000)=1/1403
By solving we get r=4.7k
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