Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 20)
20.
In a certain five-step R/2R ladder network, the smallest resistor value is 1 k
. The largest value is
. The largest value isindeterminable
2 k
10 k
20 k
Discussion:
10 comments Page 1 of 1.
Raja Tayyab said:
5 years ago
It is just a continuous 5 step R, 2R, R, 2R network.
The smallest value is are (1k) and largest value is 2R (2k). If it is 10 or 20 step network. Doesn't matter, the value is still R and 2R.
The smallest value is are (1k) and largest value is 2R (2k). If it is 10 or 20 step network. Doesn't matter, the value is still R and 2R.
(3)
Haymanot said:
5 years ago
Please give clear explanation about five steps ladder network.
(1)
FitB said:
8 years ago
What do they mean by * five steps?
Anil R said:
8 years ago
Please give me a full clear explanation.
Sunil kumar said:
8 years ago
Please clear answer.
(1)
Jagadesh said:
10 years ago
In r-2r ladder circuit the minimum and maximum resistances available are are and 2R respectively. So as given lowest resistance is 1 ohm then maximum resistance will be 2*1 ohm.
Ian Glenn said:
1 decade ago
In R-2R circuit there are only two value of resistors.
Which are the R and the 2R.
So if one of the resistance (R is equal to 1 kohm) then the other resistance is 2R or 2(1 kohm) = 2 kohm.
Which are the R and the 2R.
So if one of the resistance (R is equal to 1 kohm) then the other resistance is 2R or 2(1 kohm) = 2 kohm.
Rakesh said:
1 decade ago
In every step there are two resistors of values are in R and 2R repactively.Hence lowest resistance in the circuit is 1 ohm(given in quset.)obvious highest resisantce in the ckt will be 2 ohm.
Sandeep said:
1 decade ago
Please give clear solution.
Lavanya said:
1 decade ago
Explanation please !!
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