Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 7)
7.
A certain voltage divider consists of three 1 k
resistors in series. Which of the following load resistors will have the least effect on the output voltage?
resistors in series. Which of the following load resistors will have the least effect on the output voltage?1 M
100 k
1 k
330
Discussion:
40 comments Page 2 of 4.
Mahes said:
8 years ago
The circuit is connected in series, so current is the same through each resistor is same....though all resistant are having the same value. Each resister will consume same power (i.e. I^2R) and the voltage drop across each resistor is same(i.e. v=IR).
Sandeep k j said:
9 years ago
The effect of load on terminal voltage depends on load resistance, if the load resistance is less than current drawn by the load will be more hence terminal voltage drop is more.
Hence, most resistance load will have less effect on voltage.
Hence, most resistance load will have less effect on voltage.
Kkk said:
1 decade ago
The question is when you connect which value of the following resistor the value of output voltage doesn't alter a lot.
Out of the four 1 M is the high value of load resistance which is equal to open circuit when compared to other.
Out of the four 1 M is the high value of load resistance which is equal to open circuit when compared to other.
Amith said:
1 decade ago
The Circuit has three 1 K ohms in series & load resistor also.
Question is which of the following load resistors will have the least effect on the output voltage?
330 ohms will have the least effect on voltage across 1 K ohms.
Question is which of the following load resistors will have the least effect on the output voltage?
330 ohms will have the least effect on voltage across 1 K ohms.
Suyash singh panwar said:
1 decade ago
Three 1 ohm resistor in series then total resistance is 3 ohm
knom we connect 1 Mohm resistor then appling voltage divider rule .
Vout= R2*Vin/R1+R2 = 1*1000 kHZ/1000+3 = 0.997
the 1Mohm resistor is least effect on the output.
knom we connect 1 Mohm resistor then appling voltage divider rule .
Vout= R2*Vin/R1+R2 = 1*1000 kHZ/1000+3 = 0.997
the 1Mohm resistor is least effect on the output.
Anu said:
1 decade ago
By ohm's law V=IR.
I=V/R.
SO CURRENT INVERSELY PROPORTIONAL TO THE RESISTANCE.
Hence less will be resistance more is the current flowing so more voltage dropped and low resistance will more effect on output voltages.
I=V/R.
SO CURRENT INVERSELY PROPORTIONAL TO THE RESISTANCE.
Hence less will be resistance more is the current flowing so more voltage dropped and low resistance will more effect on output voltages.
Rahul k said:
8 years ago
By ohms law v=ir.
I=v/r.
I.e. I is inversely proportional to r.
Hence, when r is more than I is less but I is directly proportional to v hence v is also less. R=1Mohm is more in above options.
I=v/r.
I.e. I is inversely proportional to r.
Hence, when r is more than I is less but I is directly proportional to v hence v is also less. R=1Mohm is more in above options.
Harpreet Singh said:
1 decade ago
V=IR:
LET V (OUT) = IR (OUT)
When we increase output resistance highly. Then effect on output voltage is also high.
We have 1MOhm high value resistace which effects to output voltage high.
Hence Answer is 1 M Ohm.
LET V (OUT) = IR (OUT)
When we increase output resistance highly. Then effect on output voltage is also high.
We have 1MOhm high value resistace which effects to output voltage high.
Hence Answer is 1 M Ohm.
Rohit said:
1 decade ago
According to ohm's law: V=IR & I=V/R; so that output volt. is most affected when I is high & I is high when R is low, But output volt. is least affected when I is low so that R is high. R=1M
Prahlad said:
1 decade ago
OHM'S LAW:
I inversely proportional to R
And power loss = I^2R.
When more R, than less I.
And less I than less power loss.
So OUTPUT VOLTAGE is high.
So simple high are than OUTPUT VOLTAGE is high.
I inversely proportional to R
And power loss = I^2R.
When more R, than less I.
And less I than less power loss.
So OUTPUT VOLTAGE is high.
So simple high are than OUTPUT VOLTAGE is high.
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