Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 18)
18.
Two 3.3 k resistors are in series and this series combination is in parallel with a 4.7 k resistor. The voltage across one of the 3.3 k resistors is 12 V. The voltage across the 4.7 k resistor is
24 V
12 V
0 V
6 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Prajjuda said:   1 year ago
- In series, if the resistance is the same, you can just multiply the voltage by 2. So, the total voltage across the circuit in series is 12 + 12 = 24w.
- In parallel voltage will be the same so the total voltage for the 4.7kohm resistor will also be 24w.

Haider Hayat Afridi said:   7 years ago
Since the voltage is same in parallel. Here, in this case, the voltage drop across 3. 3kohm is 12V. So both are same resistor 12+12=24v.

Manju said:   8 years ago
Nice answer @Sagata.
(1)

Sri said:   1 decade ago
In series I is same but in parallel VTG is same.

VTG drops across 3.3k 12 and vtg drop at 3.3k is 12, 12+12 = 24, then vtg in parallel is same means vtg at 4.7k is 24v

S.sasikumar said:   1 decade ago
The series combination Circuit should have two 3.3k resistor and One 4.7 k resistor but One 3.3k take 12V, So series resistance are equal resistance hence the voltage added (12+12=24), the parallel is voltage same so the answer is 24.

Saeed said:   1 decade ago
12v/3.3k = 3.64mA.
Other 3.3k have 3.3k * 3.64 mA = 12v.

Now voltage add 12+12 = 24.
This 24 will acros 4.7k.
(1)

Ahmed said:   1 decade ago
KVL can be used, since all voltages in one loop is = 0 then we have two equal R and of them has 12 voltage drop.

- 12 - 12 + 24 = 0.

Sayani Basu said:   1 decade ago
Well explanation Sagata
(1)

Sagata said:   1 decade ago
Two resistances are equal therefore there voltage drop are equal.therefore the total voltage drop in the series resistance is(12+12=24V).

Now this is in parlel wid da series i.e voltage wil b same but current diff.thus ans=24V.

Arun SANKARP said:   1 decade ago
Given data:

Two 3.3 kohm resistor so=6.6 kohm
then
3.3=12v
4.7=?

So,
12/3.3=3.6

Then 3.6*6.6=23.84 appx=24 v

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