Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 2)
2.
Two 1.2 k resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
138
1,389
5,700
880
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 2 of 2.

Bhavesh Prajapati said:   1 decade ago
2 resistors in series formula is = R1+R2
so 1.2+1.2 = 2.4k ohm
now it parellel wid 3.3k ohm
parallel formula is R1*R2/R1+R2
so 2.4+3.3/2.4+3.3=1.389k ohms
killo ohms into ohms by multipication 1000
=1.38947*1000
=1389.47 ohms
=1389 ohms

Riya Thakur said:   1 decade ago
2 resistors in series formula is = R1+R2
so 1.2+1.2 = 2.4k ohm
nw it parellel wid 3.3k ohm
parellel formula is R1*R2/R1+R2
so 2.4+3.3/2.4+3.3=1.389k ohms
=1389 ohms

Anand said:   1 decade ago
Nice explaination Deepika & Madhu metha

Deepika said:   1 decade ago
Two resistors of value 2.4k ohms

i.e 1.2+1.2=2.4k ohms

Therefore R1=2.4k ohms. This R1 is connected parallel with 3.3k ohms.
we asume 3.3k ohms=R2

The parallel formula is=(R1*R2)/(R1+R2)
=2.4*3.3/(2.4+3.3)
=7.92/5.7
=1.38947k ohms

To convert the killo ohms into ohms by multipication 1000

Therefore;

=1.38947*1000
=1389.47 ohms

Madhu metha said:   1 decade ago
Two resistors of value 1.2k ohm each in series can be added up. connected in parallel with 3.3.k ohm.

((2.4*3.3)/(2.4+3.3))*1000 = 1389.47 for k


Post your comments here:

Your comments will be displayed after verification.