Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 25)
25.
Two 6 V batteries are connected series aiding across two 1.2 k
resistors in series. Current through each resistor is
resistors in series. Current through each resistor isDiscussion:
10 comments Page 1 of 1.
Pavithra said:
1 decade ago
There are two 6 volt batteries and two 1.2 kohm resistors..
i.e., the total volt=12v and the total resistance =2.4 kohms.
By ohms law,
V = I/R
I = V/R
= 12/2.4 kohms
= 5 mohms
i.e., the total volt=12v and the total resistance =2.4 kohms.
By ohms law,
V = I/R
I = V/R
= 12/2.4 kohms
= 5 mohms
Chandru said:
1 decade ago
Hey suppose 6V battery are opposing each other then it's current value will become 0A.
In this question it is not mention about the terminals arrangement of the battery ?
In this question it is not mention about the terminals arrangement of the battery ?
Gopalan T said:
9 years ago
Series aiding means 6v + 6V+ 12 v.
Total current = 12v/2.4 k ohm = 5 milli amp.
Since two 1.2 K ohm in series, current will be same in both resistors.
Total current = 12v/2.4 k ohm = 5 milli amp.
Since two 1.2 K ohm in series, current will be same in both resistors.
Swetha said:
7 years ago
@all.
If series aiding means both values are + be.
If series opposing means one value + ve & another value -ve.
If series aiding means both values are + be.
If series opposing means one value + ve & another value -ve.
(1)
Anand said:
1 decade ago
Gopal there are asking current through each resistor. I having doubt on that answer. Can you explain me briefly ?
Dhanancheyan said:
1 decade ago
Since the resistors are connected in series. Current through the resistors are same!
Sabir said:
1 decade ago
Indeed many example of question and answer for electrical motors.
Abhijeet shetkar said:
1 decade ago
The current is the same through each resistor in series circuit.
Gopal said:
1 decade ago
v=ir; i=v/r;
v=12
r=2.4k
i=12/2.4
i=5mA
v=12
r=2.4k
i=12/2.4
i=5mA
(1)
Rutu said:
5 years ago
Good explanation, Thank you @Swetha.
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