# Electrical Engineering - Series Circuits - Discussion

### Discussion :: Series Circuits - General Questions (Q.No.11)

11.

Two resistors are in series: a 5.6 k resistor and a 4.7 k resistor. The voltage drop across the 5.6 k resistor is 10 V. The voltage across the 4.7 k resistor is

 [A]. 8.39 V [B]. 10 V [C]. 2.32 V [D]. 0 V

Explanation:

No answer description available for this question.

 Monalisa said: (Jan 24, 2011) current across 5.6 kohm register =10/5.6*1000=0.00178 A so,voltage across 4.7 Kohm =.00178*4.7=8.3A

 Raju said: (Feb 2, 2011) Thank you monali

 Anurag Jaiswal said: (Jul 19, 2011) current will be same for both the register because it is in series, so if we consider current across the registers is I, Soby I=V/R; I=10/(5.6*1000)=0.001786A So Voltage across 4.7 kohm register: V=0.001786*(4.7*1000)=8.394V

 Anand said: (Jul 26, 2011) Nice explanation Anurag

 Rakesh Yadav said: (Aug 23, 2013) Current flowing through all resistance in series is same. In this question value of one resistor and voltage is given so we can find out the value of current. 10/(5.6*10^3) = 0.001785. Voltage across 4.7 k ohm is V = IR : 4.7*10^3 * 0.001785 = 8.394.

 Manirose said: (May 3, 2014) The easy method: V1/r1 = V2/r2. So, 5.7/10 = 4.7/v2. 1.785*1000 = v2/4.7. 0.001785*4.7 = v2 . V2 = 8.394.

 Sushama said: (Aug 26, 2014) R1+R2 = 5.6+4.7 = 10.3 K. I = V/10.3. V1 = 10V = 5.6XV/10.3. V = 10X10.3/5.6 = 18.39. Voltage across 4.7 K = 8.394.

 Ravi said: (Dec 7, 2014) I is same in series: So, I = v1/r1 = 10/5.6 = 1.8. v2 = I*r2 = 1.8*4.7 = 8.4.

 Vinod said: (Dec 19, 2015) v1/r1 = v2/r2. 10/5.6 = x/4.7. x = 8.39.

 Prince Manju said: (Jan 24, 2016) Because in series circuit current through the both the resistors is same so that we can multiply the 5.6k ohm resistor's current with 4.7 K resistor.

 Jagadesh said: (Feb 22, 2016) Voltage in 4.7 kv = 4.7 k*i. i = Voltage in 5.6k/5.6k. i = 10/5.6 k A. v in 4.7 k = 4.7 k*10/5.6 k. = 8.39 V.

 A C Parmar said: (Mar 5, 2016) 5.6 K Ohm = 10 V. 4.7 K Ohm = ? 4.7*10/5.6 = 8.3928571 V.

 M Salman Khan said: (Oct 17, 2016) Thanks @Anurag.

 Jatin said: (Jan 13, 2017) Thanks to all for the great explanation.

 Syed said: (Aug 20, 2017) Nice @Manirose.