### Discussion :: Series Circuits - General Questions (Q.No.11)

Monalisa said: (Jan 24, 2011) | |

current across 5.6 kohm register =10/5.6*1000=0.00178 A so,voltage across 4.7 Kohm =.00178*4.7=8.3A |

Raju said: (Feb 2, 2011) | |

Thank you monali |

Anurag Jaiswal said: (Jul 19, 2011) | |

current will be same for both the register because it is in series, so if we consider current across the registers is I, Soby I=V/R; I=10/(5.6*1000)=0.001786A So Voltage across 4.7 kohm register: V=0.001786*(4.7*1000)=8.394V |

Anand said: (Jul 26, 2011) | |

Nice explanation Anurag |

Rakesh Yadav said: (Aug 23, 2013) | |

Current flowing through all resistance in series is same. In this question value of one resistor and voltage is given so we can find out the value of current. 10/(5.6*10^3) = 0.001785. Voltage across 4.7 k ohm is V = IR : 4.7*10^3 * 0.001785 = 8.394. |

Manirose said: (May 3, 2014) | |

The easy method: V1/r1 = V2/r2. So, 5.7/10 = 4.7/v2. 1.785*1000 = v2/4.7. 0.001785*4.7 = v2 . V2 = 8.394. |

Sushama said: (Aug 26, 2014) | |

R1+R2 = 5.6+4.7 = 10.3 K. I = V/10.3. V1 = 10V = 5.6XV/10.3. V = 10X10.3/5.6 = 18.39. Voltage across 4.7 K = 8.394. |

Ravi said: (Dec 7, 2014) | |

I is same in series: So, I = v1/r1 = 10/5.6 = 1.8. v2 = I*r2 = 1.8*4.7 = 8.4. |

Vinod said: (Dec 19, 2015) | |

v1/r1 = v2/r2. 10/5.6 = x/4.7. x = 8.39. |

Prince Manju said: (Jan 24, 2016) | |

Because in series circuit current through the both the resistors is same so that we can multiply the 5.6k ohm resistor's current with 4.7 K resistor. |

Jagadesh said: (Feb 22, 2016) | |

Voltage in 4.7 kv = 4.7 k*i. i = Voltage in 5.6k/5.6k. i = 10/5.6 k A. v in 4.7 k = 4.7 k*10/5.6 k. = 8.39 V. |

A C Parmar said: (Mar 5, 2016) | |

5.6 K Ohm = 10 V. 4.7 K Ohm = ? 4.7*10/5.6 = 8.3928571 V. |

M Salman Khan said: (Oct 17, 2016) | |

Thanks @Anurag. |

Jatin said: (Jan 13, 2017) | |

Thanks to all for the great explanation. |

Syed said: (Aug 20, 2017) | |

Nice @Manirose. |

Joseph said: (Nov 16, 2019) | |

Can someone please make a figure about this question. |

#### Post your comments here:

Name *:

Email : (optional)

» Your comments will be displayed only after manual approval.