Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 17)
17.
A series circuit has a 24 V source and a total resistance of 120 
. The current through each resistor is
. The current through each resistor isDiscussion:
7 comments Page 1 of 1.
Diyatulasi said:
6 years ago
I = V/R, we get answer as 0.2 ohms.
But we want to answer in terms of mA so, converting Ohms into mA.
I =0.2 Ohms= 2*(10^-1)*(10^-2)*(10^2) =2*(10^2) mA = 200 mA.
But we want to answer in terms of mA so, converting Ohms into mA.
I =0.2 Ohms= 2*(10^-1)*(10^-2)*(10^2) =2*(10^2) mA = 200 mA.
Sameer chaudhary said:
9 years ago
As per formula v =IR and in question we have voltage = 24 volt. And R = 120 ohms.
So, I = 24/240 = 2/10 = 0.2.
Now answer in milliampere 0.2 * 10^3 = 200 MA.
So, I = 24/240 = 2/10 = 0.2.
Now answer in milliampere 0.2 * 10^3 = 200 MA.
Sachin Salve said:
1 decade ago
I = V/R
= 24/120
= 0.2 A
We have mA so divide & mult by 10^-3
= (0.2*10^-3)/10^-3
= 2000*10^-3
= 200mA
= 24/120
= 0.2 A
We have mA so divide & mult by 10^-3
= (0.2*10^-3)/10^-3
= 2000*10^-3
= 200mA
Reegan said:
7 years ago
Milliampere unit is 10^-3. Then how this answer is 200ma?
(1)
Anu said:
1 decade ago
I = v/r
= 24/120
= 0.2 in milliampere
= 200 mA
= 24/120
= 0.2 in milliampere
= 200 mA
Kiran Bhalsinge said:
1 decade ago
how can this ans. is correct
please explain
please explain
Sekar said:
6 years ago
I= V/R.
I= 24/120,
I=0.2 A or 200mA.
I= 24/120,
I=0.2 A or 200mA.
(1)
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