Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 9)
9.
A series circuit consists of a 4.7 k
, a 12 k, and a 2.2 k resistor. The resistor that has the most voltage drop is
, a 12 k, and a 2.2 k resistor. The resistor that has the most voltage drop isthe 12 k
the 2.2 k
the 4.7 k
impossible to determine from the given information
Discussion:
15 comments Page 2 of 2.
SAYANI BASU said:
1 decade ago
We know current in all resistors of a series circuit is same.
By Ohm's Law we know,
V=IR
Or, V is proportional to R.
So, drop will be higher where R is higher.
So,max voltage drop occur across 12 ohm resistor.
By Ohm's Law we know,
V=IR
Or, V is proportional to R.
So, drop will be higher where R is higher.
So,max voltage drop occur across 12 ohm resistor.
Anteshwar said:
1 decade ago
Ohms law v=ir
So,v is directly proportional to r. so as r increases v also increases. so 12k
So,v is directly proportional to r. so as r increases v also increases. so 12k
Viji said:
1 decade ago
V=IR
R2> R1,R3
SO
V2 IS MAX VTG. Ans R2=12.
R2> R1,R3
SO
V2 IS MAX VTG. Ans R2=12.
M.Nedunchezhian. said:
1 decade ago
In series circuit the "CURRENT" flows through the series resistors is "SAME".
For example we consider 1 amphere current flows in the series circuit.Then we use ohm's law we get, V=IR=1*12=12V,1*4.7=4.7V,1*2.2=2.2V.Therefore the maximum drop occurs across the 12kiloohm resistor.
For example we consider 1 amphere current flows in the series circuit.Then we use ohm's law we get, V=IR=1*12=12V,1*4.7=4.7V,1*2.2=2.2V.Therefore the maximum drop occurs across the 12kiloohm resistor.
R.Ramprakash said:
1 decade ago
R1=4.7;R2=12;R3=2.2
R=R1+R2+R3=18.9
18.9/4.7=4.02;18.9/12=1.575;18.9/2.2=8.5
so the resistor that has max.voltage drop is 12kohms which has minimum value.
R=R1+R2+R3=18.9
18.9/4.7=4.02;18.9/12=1.575;18.9/2.2=8.5
so the resistor that has max.voltage drop is 12kohms which has minimum value.
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