Electrical Engineering - Series Circuits - Discussion

How can it be measured directly by keeping anywhere it's not mentioned as series in the question, if series it was right but in parallel?

Well said @Max.

"To measure the current out of the second resistor in a circuit consisting of four resistors".

This statement tells us that all are in series because second in four means they are in one line.

@Kiran,

Not mention series or parallel, so the answer may be different.

The question is not clear. Here, it has not given as series/parallel circuits.

The ammeter is always connected in series because of we understand question also series.

It can be connected any where in the circuit because same current will be in the all resistance because of series combination.

Hence can be connected any where.

Ammeter is always connected in series with load. So, the answer is not given.

If we think the given question assume circuit is in series combination, between the second resistor end point and third resistor first point we can put the + positive problem and other source side direct give to negative problem.

So, ammeter shown deflection current on whole circuit, we can get total current of series circuit : I = I1+I2+I3.

So the answer is perfect is the ammeter - (negative) problem directly connected with fourth resistor and second resistor end point put + problem.

There is not mentioned series or parallel.

Unless & until they mention we should take it has series.