# Electrical Engineering - RLC Circuits and Resonance - Discussion

### Discussion :: RLC Circuits and Resonance - General Questions (Q.No.3)

3.

A 15 resistor, a 220 H coil, and a 60 pF capacitor are in series across an ac source. What is the bandwidth of the circuit?

 [A]. 138 MHz [B]. 10,866 Hz [C]. 1,907 Hz [D]. 138 kHz

Explanation:

No answer description available for this question.

 Amrit Kumar Mohanta said: (Jan 29, 2011) BW = R/(2*Pi*L)

 Shivani said: (Jun 9, 2011) Whats this Pi in last formula?

 Ajeet Kumar Shukla said: (Aug 8, 2011) Will there be no effect of capacitor on the bandwidth?

 Sauvik Biswas said: (Dec 21, 2011) Q=1/R*(L/C)^1/2 f=1/(2*pi*(LC)^1/2) BW=f/Q

 Parthu said: (Dec 28, 2011) BW= 1/[Q*(2*3.14*(LC)^0.5]

 Nethra said: (Jun 10, 2012) FOR SERIES CIRCUIT Q FACTOR=1/R*(C/L)^1/2 F=1/92*PI*(LC)^1/2 BW=F/Q

 Rajendar said: (Sep 21, 2012) BW=f/Q =R/(2*pi*L) (since Q=(2*pi*L)f/R)

 Rimjhim said: (Nov 9, 2013) BW = f/Q. Q = (1/R)(L/C)^1/2. = 127.65. f = 1/2*3.14*(L/C)^1/2. = 1385265.971 f/Q = 10852 = Answer.

 Rani S said: (Jan 5, 2015) BW = R/(2*Pi*L). i.e, BW = 10851.47 = 10852 Hz.

 Rammohan Rao said: (Jan 15, 2015) If it would be the question regarding series RLC resonance circuit then the bandwidth of the circuit should be R/L. Here the question is not clear.

 Surya said: (Mar 30, 2015) You mentioned 60 of capacitor. Pf means what?

 Arun said: (Jun 5, 2015) Pico farad. Pico = 10^-12.

 Shwetha said: (Jun 19, 2015) BW = R/2*3.142*L HZ.

 Abhi S G said: (Jul 23, 2018) XL=2 * π * f * l. XC=1/(2*π*f*c), when XL=XC. f=1/2* π *(LC)^1/2, And; Q=1/R * (L/C)^1/2. BW=f/Q.

 Haris said: (Jan 9, 2020) Bandwidth= Resonant Frequency/q factor.