Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion :: RLC Circuits and Resonance - General Questions (Q.No.3)

3. 

A 15 resistor, a 220 H coil, and a 60 pF capacitor are in series across an ac source. What is the bandwidth of the circuit?

[A]. 138 MHz
[B]. 10,866 Hz
[C]. 1,907 Hz
[D]. 138 kHz

Answer: Option B

Explanation:

No answer description available for this question.

Amrit Kumar Mohanta said: (Jan 29, 2011)  
BW = R/(2*Pi*L)

Shivani said: (Jun 9, 2011)  
Whats this Pi in last formula?

Ajeet Kumar Shukla said: (Aug 8, 2011)  
Will there be no effect of capacitor on the bandwidth?

Sauvik Biswas said: (Dec 21, 2011)  
Q=1/R*(L/C)^1/2
f=1/(2*pi*(LC)^1/2)
BW=f/Q

Parthu said: (Dec 28, 2011)  
BW= 1/[Q*(2*3.14*(LC)^0.5]

Nethra said: (Jun 10, 2012)  
FOR SERIES CIRCUIT Q FACTOR=1/R*(C/L)^1/2
F=1/92*PI*(LC)^1/2
BW=F/Q

Rajendar said: (Sep 21, 2012)  
BW=f/Q
=R/(2*pi*L) (since Q=(2*pi*L)f/R)

Rimjhim said: (Nov 9, 2013)  
BW = f/Q.

Q = (1/R)(L/C)^1/2.

= 127.65.

f = 1/2*3.14*(L/C)^1/2.

= 1385265.971

f/Q = 10852 = Answer.

Rani S said: (Jan 5, 2015)  
BW = R/(2*Pi*L).
i.e, BW = 10851.47 = 10852 Hz.

Rammohan Rao said: (Jan 15, 2015)  
If it would be the question regarding series RLC resonance circuit then the bandwidth of the circuit should be R/L. Here the question is not clear.

Surya said: (Mar 30, 2015)  
You mentioned 60 of capacitor. Pf means what?

Arun said: (Jun 5, 2015)  
Pico farad. Pico = 10^-12.

Shwetha said: (Jun 19, 2015)  
BW = R/2*3.142*L HZ.

Abhi S G said: (Jul 23, 2018)  
XL=2 * π * f * l.

XC=1/(2*π*f*c),
when XL=XC.

f=1/2* π *(LC)^1/2,
And;

Q=1/R * (L/C)^1/2.
BW=f/Q.

Haris said: (Jan 9, 2020)  
Bandwidth= Resonant Frequency/q factor.

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