Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 13)
13.
A resonant circuit has a lower critical frequency of 7 kHz and an upper critical frequency of 13 kHz. The bandwidth of the circuit is
Discussion:
18 comments Page 1 of 2.
Muhammad Usman Asif said:
5 years ago
Bandwidth is the sharp difference between uppercut frequency f.h and lower frequency f.l.
B.W = f.h - f.l.
B.W = 13 Hz - 7Hz = 6 Hz.
B.W = f.h - f.l.
B.W = 13 Hz - 7Hz = 6 Hz.
(2)
B.Lavanya said:
4 years ago
Bandwidth is known as upper half of frequency to lower half of frequency is known as bandwidth.
BW = f2-f1.
16-7 = 7khz.
BW = f2-f1.
16-7 = 7khz.
Sri said:
1 decade ago
The answer is six only not four
the band width = difference between two frequencies
so 13-7 will give us six not four.
the band width = difference between two frequencies
so 13-7 will give us six not four.
Ramesh said:
9 years ago
I think the answer 6 khz is right,
Is there any other method find BW?
Is there any other method find BW?
Satish kumar mohanty said:
8 years ago
Here, {(upper bandwidth - lower bandwidth)/2}+1.
Amarnath said:
1 decade ago
It will not be 4. It is 6 only.Since fo=fl-fu
RAVI KUMAR said:
9 years ago
It should be 6 because bandwidth = fu - fl.
(1)
AAA said:
1 decade ago
How comes four? I need explanation please.
Nitesh said:
9 years ago
It should be 6 kHz. Please change it.
Gjs said:
1 decade ago
How comes four? please explanation.
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