Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 12)
12.
A 90
resistor, a coil with 30
of reactance, and a capacitor with 50
of reactance are in series across a 12 V ac source. The current through the resistor is



Discussion:
8 comments Page 1 of 1.
Amol said:
4 years ago
Correct @Pravin.
As the value of Xc is greater, we must subtract XL from Xc.
As the value of Xc is greater, we must subtract XL from Xc.
Simon said:
6 years ago
Z= √ (R^2+(XL~XC)^2),
i = v/Z.
i = v/Z.
Shafi said:
6 years ago
@Pruthvi.
In question, directly reactance values are given no need to calculate.
In question, directly reactance values are given no need to calculate.
Shafi said:
6 years ago
@Pruthvi.
Formula changes depending on values of XL and XC. Here XC is greater than XL so in formulae we have to take (XC-XL) and vice versa if XL is greater.
Formula changes depending on values of XL and XC. Here XC is greater than XL so in formulae we have to take (XC-XL) and vice versa if XL is greater.
Usharani said:
6 years ago
In this question itself directly XL and XC given.
Puja said:
6 years ago
@All.
But here it is not mentioned that it is a resonant circuit.
But here it is not mentioned that it is a resonant circuit.
Pruthvi said:
6 years ago
@Praveen,
Your answer was match but you are not taken the XL & XC properly i.e XL= WL & XC = 1/wc and they are not given the value of w.
Your answer was match but you are not taken the XL & XC properly i.e XL= WL & XC = 1/wc and they are not given the value of w.
Praveen said:
1 decade ago
V=IR
I=V/R
So.. R is nothing but Z (R=Z)
Z=sqrrt(R^2+( xl-xc)) OR (R^2+(xc-xl))
z=sqrrt_(90^2+(50-30^2)
Z=SQRRT(8100+400)
z=92.195
I=V/Z=12/92.195=0.13015=130mA.
I=V/R
So.. R is nothing but Z (R=Z)
Z=sqrrt(R^2+( xl-xc)) OR (R^2+(xc-xl))
z=sqrrt_(90^2+(50-30^2)
Z=SQRRT(8100+400)
z=92.195
I=V/Z=12/92.195=0.13015=130mA.
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