Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 12)
12.
A 90 resistor, a coil with 30 of reactance, and a capacitor with 50 of reactance are in series across a 12 V ac source. The current through the resistor is
9 mA
90 mA
13 mA
130 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
8 comments Page 1 of 1.

Amol said:   4 years ago
Correct @Pravin.

As the value of Xc is greater, we must subtract XL from Xc.

Simon said:   6 years ago
Z= √ (R^2+(XL~XC)^2),
i = v/Z.

Shafi said:   6 years ago
@Pruthvi.

In question, directly reactance values are given no need to calculate.

Shafi said:   6 years ago
@Pruthvi.

Formula changes depending on values of XL and XC. Here XC is greater than XL so in formulae we have to take (XC-XL) and vice versa if XL is greater.

Usharani said:   6 years ago
In this question itself directly XL and XC given.

Puja said:   6 years ago
@All.

But here it is not mentioned that it is a resonant circuit.

Pruthvi said:   6 years ago
@Praveen,
Your answer was match but you are not taken the XL & XC properly i.e XL= WL & XC = 1/wc and they are not given the value of w.

Praveen said:   1 decade ago
V=IR
I=V/R
So.. R is nothing but Z (R=Z)
Z=sqrrt(R^2+( xl-xc)) OR (R^2+(xc-xl))
z=sqrrt_(90^2+(50-30^2)
Z=SQRRT(8100+400)
z=92.195
I=V/Z=12/92.195=0.13015=130mA.

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