# Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 12)

12.

A 90 resistor, a coil with 30 of reactance, and a capacitor with 50 of reactance are in series across a 12 V ac source. The current through the resistor is

Discussion:

8 comments Page 1 of 1.
Amol said:
4 years ago

Correct @Pravin.

As the value of Xc is greater, we must subtract XL from Xc.

As the value of Xc is greater, we must subtract XL from Xc.

Simon said:
6 years ago

Z= √ (R^2+(XL~XC)^2),

i = v/Z.

i = v/Z.

Shafi said:
6 years ago

@Pruthvi.

In question, directly reactance values are given no need to calculate.

In question, directly reactance values are given no need to calculate.

Shafi said:
6 years ago

@Pruthvi.

Formula changes depending on values of XL and XC. Here XC is greater than XL so in formulae we have to take (XC-XL) and vice versa if XL is greater.

Formula changes depending on values of XL and XC. Here XC is greater than XL so in formulae we have to take (XC-XL) and vice versa if XL is greater.

Usharani said:
6 years ago

In this question itself directly XL and XC given.

Puja said:
6 years ago

@All.

But here it is not mentioned that it is a resonant circuit.

But here it is not mentioned that it is a resonant circuit.

Pruthvi said:
6 years ago

@Praveen,

Your answer was match but you are not taken the XL & XC properly i.e XL= WL & XC = 1/wc and they are not given the value of w.

Your answer was match but you are not taken the XL & XC properly i.e XL= WL & XC = 1/wc and they are not given the value of w.

Praveen said:
1 decade ago

V=IR

I=V/R

So.. R is nothing but Z (R=Z)

Z=sqrrt(R^2+( xl-xc)) OR (R^2+(xc-xl))

z=sqrrt_(90^2+(50-30^2)

Z=SQRRT(8100+400)

z=92.195

I=V/Z=12/92.195=0.13015=130mA.

I=V/R

So.. R is nothing but Z (R=Z)

Z=sqrrt(R^2+( xl-xc)) OR (R^2+(xc-xl))

z=sqrrt_(90^2+(50-30^2)

Z=SQRRT(8100+400)

z=92.195

I=V/Z=12/92.195=0.13015=130mA.

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