Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 11)
11.
If the resistance in parallel with a parallel resonant circuit is reduced, the bandwidth
disappears
becomes sharper
increases
decreases
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 2 of 2.

Suneeth Raj said:   1 decade ago
BW=R/2pifL as resistance decrease band width decreases.

SUBHAJIT RAY said:   1 decade ago
Q = x/R when R decrease Q increase. And bandwidth inversely proportional to Q factor. That means bandwidth increase.

Gopal said:   1 decade ago
I am also having same perception with @Vasiq, also Q factor is the ratio of resistance to inductive reactance. If resistance increases then Q factor also increase & consequently Band width decreases as both inversely proportional to each other.

Vasiq said:   1 decade ago
I don't think this is right. According to wikipedia, the Q factor of a parallel RLC circuit is: R*sqrt(C/L). This implies that decreasing the resistance would decrease the Q factor. And since, Q factor and bandwidth are inversely proportional, the bandwidth would increase!

Arun said:   1 decade ago
Q = R*sqrt(C/L) for Parallel RLC.

Jeya said:   1 decade ago
Bandwidth = fr/Q --- eqn1.

fr = resonance frequency, Q=Quality factor.
fr = 1/2*pi*sqrt(LC).
Q = 1/(R*sqrt(LC).

If R decreases, Q increases from eqn1 Q increases, bandwidth decreases.


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