Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 11)
11.
If the resistance in parallel with a parallel resonant circuit is reduced, the bandwidth
Discussion:
16 comments Page 1 of 2.
Vasiq said:
1 decade ago
I don't think this is right. According to wikipedia, the Q factor of a parallel RLC circuit is: R*sqrt(C/L). This implies that decreasing the resistance would decrease the Q factor. And since, Q factor and bandwidth are inversely proportional, the bandwidth would increase!
Gopal said:
1 decade ago
I am also having same perception with @Vasiq, also Q factor is the ratio of resistance to inductive reactance. If resistance increases then Q factor also increase & consequently Band width decreases as both inversely proportional to each other.
Shashikant said:
6 years ago
In parallel RLC circuit q=r""L/c.
So when r decreases q decreases.and b.w= resonant frequency/q factor.
So if q decreases then bandwidth must increase. Make high r-value get power loss to have high q in the circuit.
So when r decreases q decreases.and b.w= resonant frequency/q factor.
So if q decreases then bandwidth must increase. Make high r-value get power loss to have high q in the circuit.
(1)
Jeya said:
1 decade ago
Bandwidth = fr/Q --- eqn1.
fr = resonance frequency, Q=Quality factor.
fr = 1/2*pi*sqrt(LC).
Q = 1/(R*sqrt(LC).
If R decreases, Q increases from eqn1 Q increases, bandwidth decreases.
fr = resonance frequency, Q=Quality factor.
fr = 1/2*pi*sqrt(LC).
Q = 1/(R*sqrt(LC).
If R decreases, Q increases from eqn1 Q increases, bandwidth decreases.
Ashwini said:
6 years ago
BW=fr/Q.
Q=2πfrL/R.
BW=frR/2πfrL.
=R/2πL.
So Resistance is proportional to Bandwidth.
As Resistance decreases Bandwidth also decreases.
Q=2πfrL/R.
BW=frR/2πfrL.
=R/2πL.
So Resistance is proportional to Bandwidth.
As Resistance decreases Bandwidth also decreases.
Gangadhar said:
7 years ago
Here;
Q = (XL/R)
BW = Fr/Q there fore
BW = (Fr*R) / XL
From the above equation, it is clear the BW is directly proportional to Resistor(R).
Q = (XL/R)
BW = Fr/Q there fore
BW = (Fr*R) / XL
From the above equation, it is clear the BW is directly proportional to Resistor(R).
Gopal Gupta said:
5 years ago
@All.
For those who are saying Q=XL/R. I want to correct them. This Q is for series RLC ckt. Given question is about parallel. So here Q=XC*R.
For those who are saying Q=XL/R. I want to correct them. This Q is for series RLC ckt. Given question is about parallel. So here Q=XC*R.
Shashi kant said:
9 years ago
We know for parallel resonance circuit Q = wRC or = R/wL. So R increases Q increases.
B.W = f. r/Q than bandwidth decreases.
B.W = f. r/Q than bandwidth decreases.
LAXMI said:
8 years ago
Q= R/(2pifL) when R decreases Q also decrease its value. And BW= fr/Q so decrease in the value of Q would increase the BW.
HAris said:
6 years ago
Simply= BW=F/Q.
Q=1/R.√(L/C).
Put in BW,
BW=F/(1/R).
B.W= F*R.
SO, BW is directly proportional to Resistance.
Q=1/R.√(L/C).
Put in BW,
BW=F/(1/R).
B.W= F*R.
SO, BW is directly proportional to Resistance.
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