Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - True or False (Q.No. 2)
                   
                                       
                                2.
The resistor voltage in an RL circuit is always out of phase with the current.
 
                                    Discussion:
20 comments Page 1 of 2.
                
                        Hemanth said: 
                         
                        5 years ago
                
                I am unable to understand this. Please explain clearly.
                
                        Naresh said: 
                         
                        8 years ago
                
                Here, the word ' always ' defines the question. It may or may not but in case of parallel the resistor voltage is not in out of phase of current.
                
                        Suraj sharma said: 
                         
                        8 years ago
                
                If it was the case of rlc circuit then at resonance condition xl = xc which makes the voltage go in phase with current, though the case is just of rl hence no possiblity that the voltage comes in phase with current.
                
                        Waheed ullah khattak said: 
                         
                        9 years ago
                
                In any case across the resistance voltage and currunt are in phas. Leading and lagging term related to capictor and inducter.
                
                     (1)
                
            
                        Sharmila said: 
                         
                        9 years ago
                
                If it is only resistor then it is in phase. It is RL circuit so, it is out of phase. i.e. is current lags voltage by some angle depends on the inductor value.
                
                     (1)
                
            
                        KINJAL VYAS said: 
                         
                        9 years ago
                
                VR along same axis or direction as that of  current  phasor i.e VR is in phase with I.
We know that in the inductor, voltage leads current by 90 degrees, so draw VL (voltage drop across inductor) perpendicular to current phasor.
                We know that in the inductor, voltage leads current by 90 degrees, so draw VL (voltage drop across inductor) perpendicular to current phasor.
                        Saurabh said: 
                         
                        1 decade ago
                
                As it is mention here voltage across resistance is in phase only with real part of current but not resultant current. So it is a true statement.
                
                        Vikash kumar said: 
                         
                        1 decade ago
                
                Lagging of voltage is due to capacitive load, leading of voltage is due to inductive load. There is no phase shift due to resistive load.
                
                     (1)
                
            
                        Siddharth mehta said: 
                         
                        1 decade ago
                
                The question is given as "resistor voltage" is out of phase not the voltage of total.
                
                        Anish said: 
                         
                        1 decade ago
                
                When RL circuit are in parallel then voltage across is not out of phase.
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