Electrical Engineering - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 1)
1.
A 1.5 k resistor and a coil with a 2.2 k inductive reactance are in series across an 18 V ac source. The power factor is
564
0.564
6.76
55.7
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 2 of 2.

Pavan said:   10 years ago
Power factor indicates efficiency of the circuit.

Kalyan G said:   5 years ago
Z=(r^2+XL^2)^1/2=2663.
P.f = cosq = r/z
0.564.
(1)

Saipriya said:   9 years ago
Describe or view the process of the answer.

Manfrizy said:   1 decade ago
R/Z = 0.405 not 0.564 as you put it Sanjeeb

Shaila kedar said:   1 decade ago
Power factor is always less than 1.

Vicky said:   9 years ago
cos(q) can never be greater than 1.
(1)

G1KUMAR said:   9 years ago
z = (r^2 + x^2)^(1/2).
Ccos = r/z.

Manoj Khodade said:   8 years ago
How to solve? please details.

SANJEEB said:   1 decade ago
COSQ=R/Z=1.5/1.5+2.2=0.564

Arpana singh said:   7 years ago
R/Z=0.405 not 0.564.
(1)


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