Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 1)
1.
A 1.5 k
resistor and a coil with a 2.2 k
inductive reactance are in series across an 18 V ac source. The power factor is


Discussion:
20 comments Page 2 of 2.
Pavan said:
10 years ago
Power factor indicates efficiency of the circuit.
Kalyan G said:
5 years ago
Z=(r^2+XL^2)^1/2=2663.
P.f = cosq = r/z
0.564.
P.f = cosq = r/z
0.564.
(1)
Saipriya said:
9 years ago
Describe or view the process of the answer.
Manfrizy said:
1 decade ago
R/Z = 0.405 not 0.564 as you put it Sanjeeb
Shaila kedar said:
1 decade ago
Power factor is always less than 1.
Vicky said:
9 years ago
cos(q) can never be greater than 1.
(1)
G1KUMAR said:
9 years ago
z = (r^2 + x^2)^(1/2).
Ccos = r/z.
Ccos = r/z.
Manoj Khodade said:
8 years ago
How to solve? please details.
SANJEEB said:
1 decade ago
COSQ=R/Z=1.5/1.5+2.2=0.564
Arpana singh said:
7 years ago
R/Z=0.405 not 0.564.
(1)
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