### Discussion :: RL Circuits - General Questions (Q.No.14)

Arjun said: (Jan 4, 2012) | |

Magnitude=( r^2+ x^2)^12 tan(phase angle) = 120/47 So ans is magnitude*phase angle = Ans D. |

Priya said: (Mar 11, 2015) | |

Z = R+jXL. = 47+j120. In polar form: = 128.87 angle 68.61. |

D Gomathi said: (Dec 24, 2015) | |

I don't understand please explain. |

Gnani said: (Feb 5, 2016) | |

R = 47; XL = 120 then R+jXL = R^2+X^2. = 47^2 + 120^2. = 128.87. tan^-1 (XL/R) = tan^-1 (120/47) = 68.8. |

B Sharath Kumar said: (Jan 31, 2017) | |

Please, anyone explain how to calculate tan inverse of 120/40 without calculator? |

Buddhadeb Singha said: (Dec 29, 2017) | |

How to calculate? 47^2 + 120^2= 128.87. |

Raj said: (Jan 30, 2018) | |

Z= R+jXL. = (47^2+120^2)1^1/2. = 128.87. = tan^-1(XL/R)=68.8. |

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