Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 19)
19.
If a load is purely inductive and the reactive power is 12 VAR, the apparent power is
Discussion:
4 comments Page 1 of 1.
Arundeep said:
1 decade ago
Apparant power = active power + reactive power.
But in purly inductive case active power = 0.
Apparnt power = 0 + 12.
= 12.
But in purly inductive case active power = 0.
Apparnt power = 0 + 12.
= 12.
Subhrajit jena said:
7 years ago
Apparent power =Reactive power÷sin(90), as it is pure inductive.
Now Apparent power=12÷1=12 VA, the required answer.
Now Apparent power=12÷1=12 VA, the required answer.
Rakesh said:
1 decade ago
Apparent power = Hole under root of (Square of active power + Square of reactive power).
Brahma said:
1 decade ago
Root of S = root (square of p + square of q).
(1)
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