Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 7)
7.
When the frequency is decreased, the impedance of a parallel RL circuit
Discussion:
8 comments Page 1 of 1.
Raju saikh said:
1 decade ago
As impidence(X) directly propotional to the frequency,
so, with decreses of frequency , impidence decreses
so, with decreses of frequency , impidence decreses
(1)
Infy said:
1 decade ago
Impedence of parallel circuit is Xl = 2piefl.
directly porpotainal to Frequency.
As frequency decreses impedence decerases
directly porpotainal to Frequency.
As frequency decreses impedence decerases
Akhil said:
1 decade ago
R in parallel with XL so total value of Z but frequency only depend on XL that is decreases.
Sarao said:
10 years ago
Why we take XL and not XC please explain me?
Subin said:
9 years ago
XC is capacitive reactance. XL is inductive reactance.
Parallel RL circuit has inductive reactance not capacitive.
Parallel RL circuit has inductive reactance not capacitive.
Prasad hajare said:
8 years ago
Solve it by using parallel combination of r and xl you will get answer, which is decrease.
Jhosaaguilar said:
8 years ago
In parallel RL circuit, try to solve first the value of admittance (Y) =sqrt ( (1/R) ^2+ (1/XL) ^2) ; XL=2*pi*f*L, meaning, when f (frequency) decreased. Your Y increased. And remember that impedance (Z) is inversely proportional to Y. Z=1/Y.
Sharan said:
8 years ago
Well explained @Jhosaaguilar.
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