Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 15)
15.
When the resistor voltage in a series RL circuit becomes less than the inductor voltage, the phase angle
Discussion:
5 comments Page 1 of 1.
Nihar Shah said:
1 decade ago
COS(phaseangle) = R/Z.
V = IZ.
If V of inductor increases, Z increases so cos(phaseangle) decreases so phase angle increases.
V = IZ.
If V of inductor increases, Z increases so cos(phaseangle) decreases so phase angle increases.
(1)
B SharathKumar said:
9 years ago
V of inductor directly proportional to the reactance of inductor when V across L greater than V across R. Xl is greater than R circuit in inductive in nature. So phase angle increases.
Alam khAN said:
9 years ago
It is explained by the phasor diagram.
Rajashekar balya said:
8 years ago
Phase angle =tan'(Vc/Vr).
Raju said:
6 years ago
Vr<Vl.
IR<IXL.
R<Xl.
Cos φ= R/Z.
IR<IXL.
R<Xl.
Cos φ= R/Z.
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