Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 11)
11.
What is the value of the hypotenuse of a right triangle whose sides are 12 and 18?
Discussion:
4 comments Page 1 of 1.
B.HEMANTH YADAV said:
1 decade ago
We can prove this problem by pythagoras theorem AC^2 = AB^2+BC^2.
12^2 = 144.
18^2 = 324.
324+144 = 468.
ROOT OF 468 = 21.63.
12^2 = 144.
18^2 = 324.
324+144 = 468.
ROOT OF 468 = 21.63.
Balamurugan C said:
1 decade ago
TAKE A- HYPOTENUSE, B-12 AND C-18
A2=B2+C2
A = SQ.ROOT OF((12X12)+(18X18))
= SQ.ROOT OF(468)
= 21.63
A2=B2+C2
A = SQ.ROOT OF((12X12)+(18X18))
= SQ.ROOT OF(468)
= 21.63
Yu Wei said:
3 years ago
Other than conventional:
It could also be 12+18i (21. 63<56. 30) or 18+12i (21. 63<33. 69).
It could also be 12+18i (21. 63<56. 30) or 18+12i (21. 63<33. 69).
Eiroth said:
7 years ago
By using Pythagoras theorem, the answer is D.
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