Electrical Engineering - RC Circuits - Discussion

Discussion Forum : RC Circuits - General Questions (Q.No. 22)
22.
The complex number 40 55° is equivalent to
55 + j55
40 + j40
45.88 + j65.52
22.94 + j32.76
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Nihar said:   1 decade ago
A<B = A(cosB+isinB).

So here,

40<55 = 40(cos55+isin55) = 22.94+i32.76.

Dilip verma said:   1 decade ago
z=root(a2+b2) where z=40 and Angle=a/b where angle=tan55 then by making equations we solve it.

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