Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 1)
1.
In the complex plane, the number 14 – j5 is located in the
Discussion:
18 comments Page 1 of 2.
Jefferson said:
3 years ago
1st quadrant (-, +).
2nd quadrant (-, -).
3rd quadrant (+, +).
4th quadrant (+, -).
2nd quadrant (-, -).
3rd quadrant (+, +).
4th quadrant (+, -).
(5)
Yu Wei said:
3 years ago
Converting it to the polar form, the polar angle would be (-)19.65 which is equal to 340.35 as you rotate clockwise. Thus, it lie in Q4.
(2)
Shalaka said:
4 years ago
Thnks @Sidhu.
Sameeksh said:
7 years ago
The tan inverse(-5/14)=-ve answer.
That implies it's in 4th quadrant or 2nd quadrant. But the real coefficient is +ve. So obviously it's in 4th quadrant.
That implies it's in 4th quadrant or 2nd quadrant. But the real coefficient is +ve. So obviously it's in 4th quadrant.
Fiords said:
9 years ago
Thanks @Sidhu.
Vikas said:
9 years ago
Nice @Sidhu.
Kiran said:
10 years ago
I don't know anything. Please anyone explain me?
Raj kumar said:
10 years ago
Can you explain please?
Vamshi said:
1 decade ago
Do we need to convert to polar for answer.
Milan patel said:
1 decade ago
In quadrant co-ordinate is write in form (cos@, sin@). So it also write as cos@+jsin@.
So on that the answer will be (cos@, -sin@) so it in fourth quadrant.
So on that the answer will be (cos@, -sin@) so it in fourth quadrant.
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