Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 8)
8.
In the complex plane, the number 4 + j3 is located in the
Discussion:
3 comments Page 1 of 1.
Uday said:
1 decade ago
+j
2nd | 1qdrent now 4+3j
| *(4+3j) r=4 and j=+3
-r---------|-------+r
3rd | 4th
|
-j
2nd | 1qdrent now 4+3j
| *(4+3j) r=4 and j=+3
-r---------|-------+r
3rd | 4th
|
-j
(1)
Chaitanya said:
1 decade ago
Angle we get from 4+j3 is +36.86 so, it will be located in first quadrant.(as we know that 1st quadrant is 0-90 degrees).
(1)
Asim said:
1 decade ago
How we got +36.86 ?
(1)
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