Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 20)
20.
A 2 k
resistor is in series with a 0.015 
F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?
resistor is in series with a 0.015 F capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?73.4 and θ = –19.5°
and θ = –19.5°707 and θ = –19.5°
and θ = –19.5°2121 and θ = –19.5°
and θ = –19.5°734 and θ = –38.9°
and θ = –38.9°Answer: Option
Explanation:
Xc = 1/2πfC = 707 Ω
Z = R - jXc = 2000 - j(707)
|z| = sqrt(R*R + Xc*Xc) = 2121 Ω
Phase angle = arctangent(Xc/R) = 19.5°
Discussion:
4 comments Page 1 of 1.
Sagar said:
8 years ago
I think the value of Xc is not correct.
Marbudki toi said:
5 years ago
Can you explain to me in detail?
Sandy said:
3 years ago
Please explain the answer.
Yu Wei said:
3 years ago
That would be :
R - (1/2πfc)i *remember that Xc is (-) while Xl is (+).
2000 - 707.3553i.
Use complex mode to convert it to polar form: 2121.4<-19.48°.
R - (1/2πfc)i *remember that Xc is (-) while Xl is (+).
2000 - 707.3553i.
Use complex mode to convert it to polar form: 2121.4<-19.48°.
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