Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 21)
21.
A 12 k
resistor is in series with a 0.02 
F capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3
0° mA, what is the source voltage expressed in polar form?
resistor is in series with a 0.02 F capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.30° mA, what is the source voltage expressed in polar form?Discussion:
4 comments Page 1 of 1.
Selva said:
1 decade ago
FROM OHM'S LAW V=IZ
Z=Sqr(R^2+Xc^2)
Xc=(1/(2*pi*f*C))
Xc=(10^3/(2*pi*1.2*0.02))
=(1000/0.15)=6666.67 ohms
Z=sqr(12000^2+6666.67^2)=13727.508 ohms
V=IZ=13727.508*0.3 mA
=4.11 volts
Z=Sqr(R^2+Xc^2)
Xc=(1/(2*pi*f*C))
Xc=(10^3/(2*pi*1.2*0.02))
=(1000/0.15)=6666.67 ohms
Z=sqr(12000^2+6666.67^2)=13727.508 ohms
V=IZ=13727.508*0.3 mA
=4.11 volts
(1)
Rimah said:
6 years ago
Why we have to the square the resistance and capacitance values?
Nomiki said:
6 years ago
The answer should be in Volts.
Chester said:
8 years ago
Answer should be in mV.
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