Discussion :: RC Circuits - General Questions (Q.No.17)
For a certain load, the true power is 150 W and the reactive power is 125 VAR. The apparent power is
Answer: Option B
No answer description available for this question.
|Shital Hadiyal said: (Jul 30, 2011)|
|Apparent Power = 125+ 150 =275/1.41=195.2w|
|Pradeep said: (Sep 17, 2011)|
|The above solution is wrong
The correct one is sqrt( 125^2 + 150^2 ) = 195.2
|E.Carlo_Ee said: (May 3, 2013)|
|Units should be in VA. i.e. 195.2VA.
True power - Watts.
Reactive power - VARS.
Apparent power - VA/KVA.
|Manikanta said: (Nov 29, 2013)|
|kva = sqrt(true power)*sqrt(reactive power).|
|Durga Prasad said: (Jun 13, 2015)|
|kva = square root of kw^2+kvar^2.|
|Bimal said: (Jan 15, 2017)|
By the help of your formula, the answer which outputted is not matched with given option. So please explain in detail.
|Manju said: (Sep 12, 2017)|
(app)^2=(tru p)^2+(react p)^2.
so, app p=sqrt of tru^2+react^2.
|Madhuri said: (Jan 11, 2018)|
|How to convert VAR power into Watt?|
|Haris said: (Jan 11, 2020)|
|The answer should be 195.25 VA.|
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