Discussion :: RC Circuits - General Questions (Q.No.18)
When the frequency of the voltage applied to a series RC circuit is increased, the phase angle
Answer: Option B
No answer description available for this question.
|Amit Kumar Saha said: (May 18, 2012)|
|We know, Xc=1/2*pi*f*c ------ i
Hence, from eqn. i, if f(frequency) increased, Xc gradually decreased.
Also we know, Phase angel= tan^-1(Xc/R)
So if Xc decreased, also phase angle gradually decreased.
|Tapash said: (Jul 9, 2015)|
|Any wide description about it.|
|Aleksandr said: (Feb 7, 2016)|
|Phase angle = arctg ((XL-XC)/R), XL = 0, phase angle = arctg(-XC/R),
So tg(alpha) = -XC/R, when XC decrease tg (alpha) from minus go to 0 to be increased.
So alpha also from minus go to 0. So the question is how you consider angle increase or decrease. So if alpha from -40 goes to 0 it's decrease or increase?
|Niru said: (Jan 8, 2018)|
Thus xc dec.
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.