Electrical Engineering - Passive Filters - Discussion

Discussion :: Passive Filters - General Questions (Q.No.13)

13. 

A series resonant band-stop filter consists of a 68 resistor, a 110 mH coil, and a 0.02 F capacitor. The internal resistance, RW, of the coil is 4 . Input voltage is 200 mV. Output voltage is taken across the coil and capacitor in series. What is the output voltage magnitude at f0?

[A]. 1.1 mV
[B]. 11.1 mV
[C]. 111 mV
[D]. 200 mV

Answer: Option B

Explanation:

No answer description available for this question.

Texugoelectrico said: (May 20, 2012)  
At the resonance frequency XL=XL, therefore we have:

Vo = [RL / (RL + R)] * Vi
= [4 / (68 + 4)] * 0.2
= 0.0111 V = 11.1 mV ---- B

Mohammad Ghouse said: (Dec 10, 2014)  
Since at Resonance XL = XC,

Therefore By Voltage Divider Rule,

Vo = Vi*[Rl/(Rl+R)].

= 0.2*[4/(68+4)].

= 11.1 mV.

Dhiraj J said: (Sep 27, 2017)  
I=200/(68+4)=2.778.

Voltage across LC = 2.778*4 = 11.08,
= 11.1mv.

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