# Electrical Engineering - Passive Filters - Discussion

### Discussion :: Passive Filters - General Questions (Q.No.13)

13.

A series resonant band-stop filter consists of a 68 resistor, a 110 mH coil, and a 0.02 F capacitor. The internal resistance, RW, of the coil is 4 . Input voltage is 200 mV. Output voltage is taken across the coil and capacitor in series. What is the output voltage magnitude at f0?

 [A]. 1.1 mV [B]. 11.1 mV [C]. 111 mV [D]. 200 mV

Answer: Option B

Explanation:

No answer description available for this question.

 Texugoelectrico said: (May 20, 2012) At the resonance frequency XL=XL, therefore we have: Vo = [RL / (RL + R)] * Vi = [4 / (68 + 4)] * 0.2 = 0.0111 V = 11.1 mV ---- B

 Mohammad Ghouse said: (Dec 10, 2014) Since at Resonance XL = XC, Therefore By Voltage Divider Rule, Vo = Vi*[Rl/(Rl+R)]. = 0.2*[4/(68+4)]. = 11.1 mV.

 Dhiraj J said: (Sep 27, 2017) I=200/(68+4)=2.778. Voltage across LC = 2.778*4 = 11.08, = 11.1mv.

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