Electrical Engineering - Passive Filters - Discussion
Discussion Forum : Passive Filters - General Questions (Q.No. 5)
5.
A parallel resonant band-pass filter consists of a 90 
resistor in series with a parallel network made up of a 60 mH coil and a 0.02 
F capacitor. The output is taken across the capacitor/coil. The coil winding has a resistance of 20 . What is the center frequency of the filter?
resistor in series with a parallel network made up of a 60 mH coil and a 0.02 F capacitor. The output is taken across the capacitor/coil. The coil winding has a resistance of 20 . What is the center frequency of the filter?Discussion:
8 comments Page 1 of 1.
Udaypratapsingh said:
6 years ago
Frequency = 1/2π√Lc.
Harshal said:
6 years ago
XL = XC is for the series RLC circuit and in this question the mentioned circuit is parallel circuit.
AhmadNour said:
6 years ago
Center frequency = Resonance Frequency.
At Resonance Frequency XL = Xc .
Fr = 1/2*p* √(L*C).
At Resonance Frequency XL = Xc .
Fr = 1/2*p* √(L*C).
Ali said:
7 years ago
How 21129.99hz came?
(1)
Rashid said:
1 decade ago
XL=Xc.
2*pi*f*L = 1/(2*pi*f*C).
f^2 = 1/(4*pi^2*L*C).
f^2 = 21129.99 hz.
f = sqrt (21129.99).
f = 4596.7 Hz.
2*pi*f*L = 1/(2*pi*f*C).
f^2 = 1/(4*pi^2*L*C).
f^2 = 21129.99 hz.
f = sqrt (21129.99).
f = 4596.7 Hz.
Nyce said:
1 decade ago
Just solve for resonant freq given the formula Fr = 1/(2pi.sqrt(LC)).
Kailash said:
1 decade ago
At resonance:
xl = xc.
sub fof l $ c ,to find f.
xl = xc.
sub fof l $ c ,to find f.
Alaa said:
1 decade ago
Explain it please.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers