Electrical Engineering - Passive Filters - Discussion

Discussion :: Passive Filters - General Questions (Q.No.5)

5. 

A parallel resonant band-pass filter consists of a 90 resistor in series with a parallel network made up of a 60 mH coil and a 0.02 F capacitor. The output is taken across the capacitor/coil. The coil winding has a resistance of 20 . What is the center frequency of the filter?

[A]. 459 Hz
[B]. 4,591 Hz
[C]. 999 Hz
[D]. 2,176 Hz

Answer: Option B

Explanation:

No answer description available for this question.

Alaa said: (Dec 31, 2014)  
Explain it please.

Kailash said: (Feb 9, 2015)  
At resonance:

xl = xc.

sub fof l $ c ,to find f.

Nyce said: (Mar 27, 2015)  
Just solve for resonant freq given the formula Fr = 1/(2pi.sqrt(LC)).

Rashid said: (Jun 13, 2015)  
XL=Xc.

2*pi*f*L = 1/(2*pi*f*C).

f^2 = 1/(4*pi^2*L*C).
f^2 = 21129.99 hz.
f = sqrt (21129.99).
f = 4596.7 Hz.

Ali said: (Aug 31, 2018)  
How 21129.99hz came?

Ahmadnour said: (May 29, 2019)  
Center frequency = Resonance Frequency.

At Resonance Frequency XL = Xc .
Fr = 1/2*p* √(L*C).

Harshal said: (Jul 29, 2019)  
XL = XC is for the series RLC circuit and in this question the mentioned circuit is parallel circuit.

Udaypratapsingh said: (Sep 17, 2019)  
Frequency = 1/2π√Lc.

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