# Electrical Engineering - Passive Filters - Discussion

### Discussion :: Passive Filters - General Questions (Q.No.5)

5.

A parallel resonant band-pass filter consists of a 90 resistor in series with a parallel network made up of a 60 mH coil and a 0.02 F capacitor. The output is taken across the capacitor/coil. The coil winding has a resistance of 20 . What is the center frequency of the filter?

 [A]. 459 Hz [B]. 4,591 Hz [C]. 999 Hz [D]. 2,176 Hz

Explanation:

No answer description available for this question.

 Alaa said: (Dec 31, 2014) Explain it please.

 Kailash said: (Feb 9, 2015) At resonance: xl = xc. sub fof l \$ c ,to find f.

 Nyce said: (Mar 27, 2015) Just solve for resonant freq given the formula Fr = 1/(2pi.sqrt(LC)).

 Rashid said: (Jun 13, 2015) XL=Xc. 2*pi*f*L = 1/(2*pi*f*C). f^2 = 1/(4*pi^2*L*C). f^2 = 21129.99 hz. f = sqrt (21129.99). f = 4596.7 Hz.

 Ali said: (Aug 31, 2018) How 21129.99hz came?

 Ahmadnour said: (May 29, 2019) Center frequency = Resonance Frequency. At Resonance Frequency XL = Xc . Fr = 1/2*p* √(L*C).

 Harshal said: (Jul 29, 2019) XL = XC is for the series RLC circuit and in this question the mentioned circuit is parallel circuit.

 Udaypratapsingh said: (Sep 17, 2019) Frequency = 1/2π√Lc.