Discussion :: Passive Filters - General Questions (Q.No.7)
|Priyadarshini said: (Jun 5, 2015)|
|Fc = 1/(2*pi*sqrt(L*C)) = 1/(2*pi*sqrt(8u*120p) = 5.136Mhz app = to 5.14 Mhz.|
|Sarath said: (Jul 29, 2015)|
|How to work out without calculator?|
|Ahmed said: (Aug 6, 2016)|
|Where is the resistor value?|
|Sewak said: (Oct 28, 2016)|
|Resistor value not required for calculation of centre (resonance) frequency. Xl = Xc.
The resistor value is required while calculating the critical frequency. R = Xc, R = Xl.
|Sanju said: (Nov 11, 2016)|
|It's wrong. For parallel resonant circuit, fr = sqrt ( (1/LC) - (R^2/L^2) )/(2 * pi).|
|Nabeel Alrawi said: (Dec 3, 2016)|
|It is not a parallel resonant, it is a series resonant, so the calculation done by Priyadarshini is correct.|
|Bharath said: (Mar 19, 2017)|
|Find voltage expression, we will be having (Xl-Xc) expression in the denominator.
Vo= 1/(R * (XL-Xc)/(Xl*Xc) + 1).
So max. voltage is occured, If XL=XC.
Hence, not exactly parallel.
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