### Discussion :: Passive Filters - General Questions (Q.No.7)

Priyadarshini said: (Jun 5, 2015) | |

Fc = 1/(2*pi*sqrt(L*C)) = 1/(2*pi*sqrt(8u*120p) = 5.136Mhz app = to 5.14 Mhz. |

Sarath said: (Jul 29, 2015) | |

How to work out without calculator? |

Ahmed said: (Aug 6, 2016) | |

Where is the resistor value? |

Sewak said: (Oct 28, 2016) | |

Resistor value not required for calculation of centre (resonance) frequency. Xl = Xc. The resistor value is required while calculating the critical frequency. R = Xc, R = Xl. |

Sanju said: (Nov 11, 2016) | |

It's wrong. For parallel resonant circuit, fr = sqrt ( (1/LC) - (R^2/L^2) )/(2 * pi). |

Nabeel Alrawi said: (Dec 3, 2016) | |

It is not a parallel resonant, it is a series resonant, so the calculation done by Priyadarshini is correct. |

Bharath said: (Mar 19, 2017) | |

Find voltage expression, we will be having (Xl-Xc) expression in the denominator. Vo= 1/(R * (XL-Xc)/(Xl*Xc) + 1). So max. voltage is occured, If XL=XC. Hence, not exactly parallel. |

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