Electrical Engineering - Passive Filters - Discussion
Discussion Forum : Passive Filters - General Questions (Q.No. 8)
8.
A series resonant band-pass filter consists of a 2 mH coil, a 0.005 
F capacitor, and a 120 
resistor. The winding resistance of the coil is 12 . The output voltage is taken off the resistor. Input voltage is 12 Vrms. What is the output voltage magnitude at the center frequency (f0)?
F capacitor, and a 120 resistor. The winding resistance of the coil is 12 . The output voltage is taken off the resistor. Input voltage is 12 Vrms. What is the output voltage magnitude at the center frequency (f0)?Discussion:
4 comments Page 1 of 1.
Miles D Abarquez said:
1 year ago
Voltage divider:
Vres = 12V(120)/120+12.
Vres = 10.9 V.
Vres = 12V(120)/120+12.
Vres = 10.9 V.
Raja Bilal said:
1 decade ago
Center frequency means critical frequency and it is calculated on the basis of critical frequency.
Vasiq said:
1 decade ago
But your solution doesn't account for the center frequency equation.
(2)
Abhishek maji said:
1 decade ago
We know that at series resonance inductive reactance = capacitive reactance. Therefore total impedance is only the net resistance of the circuit. Here the net resistance is = (120+12) =132 ohm.
So, current at the resonant condition = 12V/132 ohm = 0.09A.
As the output voltage is taken off the resistor, so the output voltage at center frequency is = (0.09*120) = 10.9V.
So, current at the resonant condition = 12V/132 ohm = 0.09A.
As the output voltage is taken off the resistor, so the output voltage at center frequency is = (0.09*120) = 10.9V.
(4)
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