# Electrical Engineering - Passive Filters - Discussion

### Discussion :: Passive Filters - General Questions (Q.No.8)

8.

A series resonant band-pass filter consists of a 2 mH coil, a 0.005 F capacitor, and a 120 resistor. The winding resistance of the coil is 12 . The output voltage is taken off the resistor. Input voltage is 12 Vrms. What is the output voltage magnitude at the center frequency (f0)?

 [A]. 10.9 V [B]. 1.09 V [C]. 1.1 V [D]. 12 V

Explanation:

No answer description available for this question.

 Abhishek Maji said: (Jun 21, 2012) We know that at series resonance inductive reactance = capacitive reactance. Therefore total impedance is only the net resistance of the circuit. Here the net resistance is = (120+12) =132 ohm. So, current at the resonant condition = 12V/132 ohm = 0.09A. As the output voltage is taken off the resistor, so the output voltage at center frequency is = (0.09*120) = 10.9V.

 Vasiq said: (Jan 19, 2015) But your solution doesn't account for the center frequency equation.

 Raja Bilal said: (Feb 6, 2015) Center frequency means critical frequency and it is calculated on the basis of critical frequency.