Electrical Engineering - Passive Filters - Discussion

Discussion :: Passive Filters - General Questions (Q.No.8)


A series resonant band-pass filter consists of a 2 mH coil, a 0.005 F capacitor, and a 120 resistor. The winding resistance of the coil is 12 . The output voltage is taken off the resistor. Input voltage is 12 Vrms. What is the output voltage magnitude at the center frequency (f0)?

[A]. 10.9 V
[B]. 1.09 V
[C]. 1.1 V
[D]. 12 V

Answer: Option A


No answer description available for this question.

Abhishek Maji said: (Jun 21, 2012)  
We know that at series resonance inductive reactance = capacitive reactance. Therefore total impedance is only the net resistance of the circuit. Here the net resistance is = (120+12) =132 ohm.

So, current at the resonant condition = 12V/132 ohm = 0.09A.

As the output voltage is taken off the resistor, so the output voltage at center frequency is = (0.09*120) = 10.9V.

Vasiq said: (Jan 19, 2015)  
But your solution doesn't account for the center frequency equation.

Raja Bilal said: (Feb 6, 2015)  
Center frequency means critical frequency and it is calculated on the basis of critical frequency.

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