Electrical Engineering - Passive Filters - Discussion
Discussion Forum : Passive Filters - General Questions (Q.No. 6)
6.
An RL high-pass filter consists of a 470 
resistor and a 600 mH coil. The output is taken across the coil. The circuit's critical frequency is
resistor and a 600 mH coil. The output is taken across the coil. The circuit's critical frequency isDiscussion:
10 comments Page 1 of 1.
Uday pratap said:
6 years ago
Critical frequency= R/2πL.
Aamir said:
10 years ago
Well, of course the cut-off frequency is when XL = R.
XL = ωL = 2*F*L.
And the time constant for LR circuit is L/R.
Therefore, the cut-off frequency, no matter if High-Pass/ Low-Pass: fc = R/(2*L).
XL = ωL = 2*F*L.
And the time constant for LR circuit is L/R.
Therefore, the cut-off frequency, no matter if High-Pass/ Low-Pass: fc = R/(2*L).
Umesh patil said:
10 years ago
Which formula you are using, I can't understand.
Just I know about.
F = 1/[2*pie*{sqr root(LC)}].
After solving we can't get given answer.
Just I know about.
F = 1/[2*pie*{sqr root(LC)}].
After solving we can't get given answer.
Shalin said:
1 decade ago
Z = R+jwL. For critical frequency, R = wL.
i.e. R = 2*pi*f*L.
So f = R/(2*pi*L) -> critical frequency.
i.e. R = 2*pi*f*L.
So f = R/(2*pi*L) -> critical frequency.
Havish said:
1 decade ago
The transfer function for this ckt will be:
|Vo/Vi(jw)| = w/[w^2 + (r/l)^2]^(1/2)
This Magnitude is
Zero for w--> 0
Unity for w--> inf
Critical freq will be that freq for which Magnitude is 0.707(i.e 1/sqrt(2))
Hence
Wc= r/l or Fc= r/2*pi*l
|Vo/Vi(jw)| = w/[w^2 + (r/l)^2]^(1/2)
This Magnitude is
Zero for w--> 0
Unity for w--> inf
Critical freq will be that freq for which Magnitude is 0.707(i.e 1/sqrt(2))
Hence
Wc= r/l or Fc= r/2*pi*l
Rekha said:
1 decade ago
F=R/(2*PI*L)
=470/(2*3.14*600*10-3)
=125HZ
=470/(2*3.14*600*10-3)
=125HZ
(1)
Kiran kumar said:
1 decade ago
I'm not getting the answer can any one explain me.
Sushil gaind said:
1 decade ago
fc =R/2*pi*L
Raju said:
1 decade ago
Use this formula critical frequency is = 1*R/2*pi*L.
Nil said:
1 decade ago
How? please explain.
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