Electrical Engineering - Passive Filters - Discussion

Discussion Forum : Passive Filters - General Questions (Q.No. 2)
2.
An RL low-pass filter consists of a 5.6 mH coil and a 3.3 k resistor. The output voltage is taken across the resistor. The circuit's critical frequency is
93.8 kHz
93.8 Hz
861 Hz
86.12 kHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

HAris said:   6 years ago
No, @SANA.

Critical frequency is the highest magnitude of frequency above which the waves penetrate the ionosphere and below which the waves are reflected back from the ionosphere.

Ionosphere: The layer of the earth's atmosphere which contains a high concentration of ions and free electrons and is able to reflect radio waves.

CUT OFF FREQUENCY: It is a level above or below at which the system fails to operate.
(1)

Sonu kumar said:   7 years ago
F =R/2πL,
= 3300/2*3.14*.0056,
= 3300/6.28*.0056,
= 33*10^8/628*56,
= 33*10^8/35168,
= 93835hz or,
= 93.8khz.
(1)

Sana said:   9 years ago
Is critical and cut off frequency are same?

Mshal said:   10 years ago
At Resonant state of series RLC circuit, Z = R = (XL-XC).

Since R & L are given, R = XL but XL = 2*π*F*L.

Therefore 3.3k ohms = 2*3.1416*F*5.6 millihenry;

F = 93.78 HZ.
(1)

PESCE said:   1 decade ago
Critical frequency is a frequency at which I is maximum in RLC circuit.

i.e, when R=sqrt (XL*XL-Xc*Xc).

Here, Xc = 0 (since RC ckt).

So.

R = XL.

But XL = 2*pie*f*L.

Hence R = 2*pie*f*L.

F = R/2*pie*L.
(1)

Jon said:   1 decade ago
Using R = XL.

Then R = 2*pie*freq*L.

Freq. = R/(2*pie*L).

= 3300/(2*3.1416*.0056).

Freq. = 93,787 Hz or 93.8 KHz.
(1)

ShaHuL said:   1 decade ago
Critical frequency/Bandwidth = R/ (2*3. 14*L).

Naga mallesh said:   1 decade ago
When R = XL its called critical frequency.

Shankarling.patil said:   1 decade ago
What is critical frequency. Please tell me friends.

Asha said:   1 decade ago
Critical frequency=R/2*PIE*L


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