Electrical Engineering - Passive Filters - Discussion

Discussion :: Passive Filters - General Questions (Q.No.9)


An RC low-pass filter consists of a 120 resistor and a 0.002 F capacitor. The output is taken across the capacitor. The circuit's critical frequency is

[A]. 333 kHz
[B]. 633 kHz
[C]. 331 kHz
[D]. 60 kHz

Answer: Option B


No answer description available for this question.

Manikandan said: (Sep 10, 2012)  
Capacitive reactance xc= 1/ ( (2* (22/7) fc.

Ian Glenn said: (Jul 28, 2013)  
fc = 1/(2*pi*R*C).

= 1/(2*3.1416*120*.002x10^-6).

= 633khz.

Joseph said: (Nov 27, 2013)  
a) In order to find the critical frequency what is the need of including resistance (fc = 1/(2*pi*R*C)).

b) We can easily find the critical frequency as
xc= 1/ ( (2* (22/7) fc.

What is the correct method we need to follow?

Mathews said: (May 30, 2017)  
Hi, I am getting 663.481khz.

Can anyone help me to get the correct solution?

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