Electrical Engineering - Passive Filters - Discussion
Discussion Forum : Passive Filters - General Questions (Q.No. 9)
9.
An RC low-pass filter consists of a 120 
resistor and a 0.002 
F capacitor. The output is taken across the capacitor. The circuit's critical frequency is
resistor and a 0.002 F capacitor. The output is taken across the capacitor. The circuit's critical frequency isDiscussion:
5 comments Page 1 of 1.
Fazal jamil said:
4 years ago
Hi, I am getting 663.481khz. Please anyone help me.
Mathews said:
8 years ago
Hi, I am getting 663.481khz.
Can anyone help me to get the correct solution?
Can anyone help me to get the correct solution?
Joseph said:
1 decade ago
a) In order to find the critical frequency what is the need of including resistance (fc = 1/(2*pi*R*C)).
b) We can easily find the critical frequency as
xc= 1/ ( (2* (22/7) fc.
What is the correct method we need to follow?
b) We can easily find the critical frequency as
xc= 1/ ( (2* (22/7) fc.
What is the correct method we need to follow?
Ian Glenn said:
1 decade ago
fc = 1/(2*pi*R*C).
= 1/(2*3.1416*120*.002x10^-6).
= 633khz.
= 1/(2*3.1416*120*.002x10^-6).
= 633khz.
ManikandaN said:
1 decade ago
Capacitive reactance xc= 1/ ( (2* (22/7) fc.
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