Electrical Engineering - Passive Filters - Discussion
Discussion :: Passive Filters - General Questions (Q.No.16)
| 16. |
At a certain frequency, the output voltage of a filter is 6 V and the input is 12 V. The voltage ratio in decibels is |
| [A]. |
6.02 dB | | [B]. |
–6.02 dB | | [C]. |
12.04 dB | | [D]. |
–12.04 dB |
Answer: Option B
Explanation:
No answer description available for this question.
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Jill Scar said:
(Oct 10, 2015)
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| Why is it negative? |
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Pavithra said:
(Oct 14, 2015)
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| Always the ratio is first output voltage (6) then input voltage (12) that's why it is negative. |
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Shan said:
(Nov 27, 2015)
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| Wrong @Pavithra that negative due to we convert into the decibel scale. |
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Sudhir said:
(Apr 11, 2016)
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Use this formula to convert the voltages to decibels:
20 * Log (Vout / Vin) = dB. |
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Shafi said:
(Mar 14, 2017)
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How to calculate decibel values without calci?
Can anyone suggest me. |
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Suma said:
(Jun 12, 2017)
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| Here, 20log(Vout/Vin) = 20log (6/12) = -6.02dB. |
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Sushma said:
(Jun 27, 2019)
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| Please, can anyone tell how to calculate dB and why it is negative? |
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Majid Mahmood said:
(Aug 19, 2019)
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| Db = 20logvout/vin so 20(log6/12) = 20 * (-0.3010) = -6.02db. |
