Electrical Engineering - Passive Filters - Discussion

Discussion Forum : Passive Filters - General Questions (Q.No. 16)
16.
At a certain frequency, the output voltage of a filter is 6 V and the input is 12 V. The voltage ratio in decibels is
6.02 dB
–6.02 dB
12.04 dB
–12.04 dB
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
8 comments Page 1 of 1.

Majid Mahmood said:   6 years ago
Db = 20logvout/vin so 20(log6/12) = 20 * (-0.3010) = -6.02db.

Sushma said:   6 years ago
Please, can anyone tell how to calculate dB and why it is negative?

Suma said:   8 years ago
Here, 20log(Vout/Vin) = 20log (6/12) = -6.02dB.

Shafi said:   8 years ago
How to calculate decibel values without calci?

Can anyone suggest me.

Sudhir said:   9 years ago
Use this formula to convert the voltages to decibels:

20 * Log (Vout / Vin) = dB.

Shan said:   10 years ago
Wrong @Pavithra that negative due to we convert into the decibel scale.

Pavithra said:   10 years ago
Always the ratio is first output voltage (6) then input voltage (12) that's why it is negative.

Jill scar said:   10 years ago
Why is it negative?

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