# Electrical Engineering - Passive Filters - Discussion

### Discussion :: Passive Filters - General Questions (Q.No.1)

1.

In a certain parallel resonant band-pass filter, the resonant frequency is 14 kHz. If the bandwidth is 4 kHz, the lower frequency

 [A]. is 7 kHz [B]. is 10 kHz [C]. is 12 kHz [D]. cannot be determined

Explanation:

No answer description available for this question.

 Alex.Jangam said: (Jan 30, 2012) Mid frequency is 14 KHz, Band width =4kHz So frequesncy range is 14+ 4/2 = 16 Khz on high pass and 14- 4/2 = 12 KHz on low pass.

 Ashok said: (Nov 2, 2012) The resonant frequency is 14 kHz. Band Width is 4 KHz then multiply the band width with 4. 4KHz * 4= 16KHz. High frequency is below the 4KHz and Low Frequency is Near the 16KHz then the resultant Low Frequency is 12KHz.

 Sanjeev Singh said: (Jul 21, 2013) The resonant frequency is 14 kHz. Band Width is 4 KHz. High frequency = resonant frequency+B.w/2, So Hf = 14+4/2 = 16. Lower frequency = resonant frequency-B.w/2, So Lf = 14-4/2 = 12. Answer C.

 Chinna said: (Dec 30, 2013) B.W = f2-f1 = 4hz. fr^2 = f1*f2 = 196. By solving above eq...f1 = 12hz.

 Rauf said: (Aug 6, 2016) It's very good to know and improve the electrical knowledge. Thank you.

 Giridhar K said: (Sep 23, 2016) Resonant frequency = G.M(geometric mean) of f1 & f2. fr = root of (f1 & f2). For High quality factor circuits Q >> 5, ckts approximately A.M of f1 & f2. fr = 0.5(f1 + f2).

 Karthik.Mg said: (Aug 22, 2018) 14-4/2= 12 how? Please explain me.

 Veeresh said: (Jun 11, 2019) Thanks for solving this clearly @Sanjeev sing.

 Pavan Kumar said: (Sep 16, 2019) Low pass 14-4/2 = 12kHz.

 Lakshmi Apoorva said: (Apr 7, 2020) Thanks for explaining Everyone.