Electrical Engineering - Passive Filters - Discussion

Discussion :: Passive Filters - General Questions (Q.No.1)

1. 

In a certain parallel resonant band-pass filter, the resonant frequency is 14 kHz. If the bandwidth is 4 kHz, the lower frequency

[A]. is 7 kHz
[B]. is 10 kHz
[C]. is 12 kHz
[D]. cannot be determined

Answer: Option C

Explanation:

No answer description available for this question.

Alex.Jangam said: (Jan 30, 2012)  
Mid frequency is 14 KHz, Band width =4kHz

So frequesncy range is

14+ 4/2 = 16 Khz on high pass and 14- 4/2 = 12 KHz on low pass.

Ashok said: (Nov 2, 2012)  
The resonant frequency is 14 kHz.
Band Width is 4 KHz then multiply the band width with 4.
4KHz * 4= 16KHz.
High frequency is below the 4KHz and Low Frequency is Near the 16KHz then the resultant Low Frequency is 12KHz.

Sanjeev Singh said: (Jul 21, 2013)  
The resonant frequency is 14 kHz.

Band Width is 4 KHz.

High frequency = resonant frequency+B.w/2, So Hf = 14+4/2 = 16.

Lower frequency = resonant frequency-B.w/2, So Lf = 14-4/2 = 12.

Answer C.

Chinna said: (Dec 30, 2013)  
B.W = f2-f1 = 4hz.

fr^2 = f1*f2 = 196.

By solving above eq...f1 = 12hz.

Rauf said: (Aug 6, 2016)  
It's very good to know and improve the electrical knowledge. Thank you.

Giridhar K said: (Sep 23, 2016)  
Resonant frequency = G.M(geometric mean) of f1 & f2.
fr = root of (f1 & f2).

For High quality factor circuits Q >> 5, ckts approximately A.M of f1 & f2. fr = 0.5(f1 + f2).

Karthik.Mg said: (Aug 22, 2018)  
14-4/2= 12 how?

Please explain me.

Veeresh said: (Jun 11, 2019)  
Thanks for solving this clearly @Sanjeev sing.

Pavan Kumar said: (Sep 16, 2019)  
Low pass 14-4/2 = 12kHz.

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