Electrical Engineering - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 20)
20.
Three 47 resistors are connected in parallel across a 110 volt source. The current drawn from the source is approximately
2.3 A
780 mA
47 mA
7.06 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 2 of 2.

Pritam said:   10 years ago
It should be 7.02 amp.

I = 110*3/47 = 7.0212 amp.
(2)

Anomie said:   7 years ago
(47^-1*3)^-1 = 15.666.
110/15.666 = 7.02A.

Devendra said:   1 decade ago
Why resitence is multiplid by 3 ?


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