# Electrical Engineering - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 20)

20.

Three 47 resistors are connected in parallel across a 110 volt source. The current drawn from the source is approximately

Discussion:

13 comments Page 1 of 2.
Anomie said:
5 years ago

(47^-1*3)^-1 = 15.666.

110/15.666 = 7.02A.

110/15.666 = 7.02A.

Poovarasan said:
8 years ago

If the resistor is connected in series across an 110-volt source.

What will be the answer?

What will be the answer?

Raj said:
8 years ago

I tried the calculation in calci, it gives 100/15.6 is 6.38. I am confused, please help me.

Pritam said:
8 years ago

It should be 7.02 amp.

I = 110*3/47 = 7.0212 amp.

I = 110*3/47 = 7.0212 amp.

(2)

Heartless boy (omi) said:
1 decade ago

Req- 47/3.

= 15.67.

Now,

I = V/R.

= 110/15.67.

= 7.06 amp.

= 15.67.

Now,

I = V/R.

= 110/15.67.

= 7.06 amp.

(2)

Debaraj sethi said:
1 decade ago

Parallel in resistance is same value r/n = 47/3 = 15.66.

Rt = 15.66.

V= 110.

I = 110/15.66 = 7.06v.

Rt = 15.66.

V= 110.

I = 110/15.66 = 7.06v.

Sathis said:
1 decade ago

V = IR,

V = 110,

R = 15.6{Parallel in resistance so, r = 1/r1+1/r2+1/r3(3 phase)}.

I = V/R = 110/15.6 = 7.06V.

V = 110,

R = 15.6{Parallel in resistance so, r = 1/r1+1/r2+1/r3(3 phase)}.

I = V/R = 110/15.6 = 7.06V.

Surendra said:
1 decade ago

Given 3 resistances are connected in parallel.

Each resistance value (R) = 47 ohm.

Two resistance value is 23.5.

Resistance 23.5 is parallel to another 45ohm resistor.

The value of (Req) =15. 66.

We can know formulla I=V/R.

The value of (I) is=7.02A The approximate answer given problem is 7.6.

Each resistance value (R) = 47 ohm.

Two resistance value is 23.5.

Resistance 23.5 is parallel to another 45ohm resistor.

The value of (Req) =15. 66.

We can know formulla I=V/R.

The value of (I) is=7.02A The approximate answer given problem is 7.6.

(1)

Mukesh Kumar said:
1 decade ago

1/R=1/R1+1/R2+1/R3=1/47+1/47+1/47=3/47

R=47/3=15.67

I=V/R=110/15.67=7.06A

R=47/3=15.67

I=V/R=110/15.67=7.06A

(3)

Christan said:
1 decade ago

Equation should be

Req=R/N

Req=R1/1+R2/1+R3/1

Req=47/3

Req=15.6 ohms

I=V/R

I=110/15.6

I=7.06 A

Req=R/N

Req=R1/1+R2/1+R3/1

Req=47/3

Req=15.6 ohms

I=V/R

I=110/15.6

I=7.06 A

(3)

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