Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 21)
21.
There is a total of 800 mA of current into four parallel resistors. The currents through three of the resistors are 40 mA, 70 mA, and 200 mA. The current through the fourth resistor is
Discussion:
2 comments Page 1 of 1.
Prabhupada said:
2 years ago
Right, thanks @Anand.
Anand said:
1 decade ago
Total current=sum of the current across parallel circuit,
800=40+70+200-I,so
I=800-(40+70+200)=800-310=490 MA
800=40+70+200-I,so
I=800-(40+70+200)=800-310=490 MA
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