Electrical Engineering - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 21)
21.
There is a total of 800 mA of current into four parallel resistors. The currents through three of the resistors are 40 mA, 70 mA, and 200 mA. The current through the fourth resistor is
490 mA
800 mA
310 mA
0 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Prabhupada said:   1 year ago
Right, thanks @Anand.

Anand said:   1 decade ago
Total current=sum of the current across parallel circuit,
800=40+70+200-I,so
I=800-(40+70+200)=800-310=490 MA

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