Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 13)
13.
Four resistors of equal value are connected in parallel. If the total voltage is 15 V and the total resistance is 600 
, the current through each parallel resistor is
, the current through each parallel resistor isDiscussion:
7 comments Page 1 of 1.
SHUBHAM said:
8 years ago
WE KNOW THAT V=IR.
I= V/R.
ACCORDING TO QUE. V=15v, R= 600.
I = 15/600= 0.025 A.
BIT THE CURRENT IS DIVIDING IN 4 PARALLEL CKT SO,
I in each ckt is = 0.025/4=0.00625 A ( OPTION NOT GIVEN),
SO 1 A= 1000ma.
0.00620A= 0.00625*1000= 6.25 ma in each circuit.
I= V/R.
ACCORDING TO QUE. V=15v, R= 600.
I = 15/600= 0.025 A.
BIT THE CURRENT IS DIVIDING IN 4 PARALLEL CKT SO,
I in each ckt is = 0.025/4=0.00625 A ( OPTION NOT GIVEN),
SO 1 A= 1000ma.
0.00620A= 0.00625*1000= 6.25 ma in each circuit.
(1)
Attitude said:
8 years ago
R/4=600.
R=2400.
I=15/2400.
I=6.25ma.
R=2400.
I=15/2400.
I=6.25ma.
(1)
Shilpa said:
9 years ago
Why can't we do like this,
V = 15v.
Total R = 600 ohms; each Rs. = R*4 = 600*4 = 2000 ohms.
Current I = V/R.
I = 15/2000.
I = 7.5 mA.
V = 15v.
Total R = 600 ohms; each Rs. = R*4 = 600*4 = 2000 ohms.
Current I = V/R.
I = 15/2000.
I = 7.5 mA.
LAKSHMI said:
9 years ago
Thank you for explaining the answer @Mani & @Coolbree.
Mani said:
9 years ago
I = v/r.
r = 600, v=15.
So, I =15/600 = 0.025.
I = 0.025/4,
I = 0.00625,
I = 6.25mA.
r = 600, v=15.
So, I =15/600 = 0.025.
I = 0.025/4,
I = 0.00625,
I = 6.25mA.
Anand said:
1 decade ago
@Coolbree
Nice explanation.
Nice explanation.
Coolbree said:
1 decade ago
V=IR, I=V/R=15/600=0.025
I(total)=I(r1)+I(r2)+I(r3)+I(r4)=4I ; (r1=r2=r3=r4)
I= I(total)/4= 0.025/4= 0.00625= 6.25e-3mA
I(total)=I(r1)+I(r2)+I(r3)+I(r4)=4I ; (r1=r2=r3=r4)
I= I(total)/4= 0.025/4= 0.00625= 6.25e-3mA
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